Sorry if this question is already asked. After new changes i am not able to judge that if anyone has posted to the thread after me where i have posted. Previously judgement was easy based on circle infront of post title. Now circle remains white bordered even there is some coments after me. If anybody knows please let me know.
Your query is bit not clear. Do you want to save all 3 language names into one array. If user select any language then set selected language in cookie. when page is loaded check cookie value and based on that fetch content.. Is that so??
Apart from readymade script, if you still want to make your own code: 1) Design database tables. e.g autoId chatSession fromUserId toUserId message dateTime 2) There will be one div and one text area for design view. 3) When user type something in textarea and press enter trigger javascript and call ajax to insert textarea's value in database. make sure you use proper fromUserId and toUserId to insert in database. 4) In div after every 2 sec, call ajax and if there is any new entry in database based on chatSession then show it in div.
I am adding code in post, and clicking on reply button. Codes are not highlighted. I thought i don't know how to use code tag but when i refreshed page it shows highlighting. Sorry if this post is repeated question. Also sometimes i need to delete last post.. Will it be posible in new edition?
$query="SELECT admission_no FROM student_info WHERE student_info.admission_no='$admission_no'";
$result=mysql_query($query);
$num_rows = mysql_num_rows($result);
if($num_rows > 0)
{
// admission no already exist in system
}
else
{
// admission no not exist
}
PHP is server side language while javascript is client side. You can not combine both. If you want to use php functionality in javascript you can use ajax which will send js data to php and will return with php output.
What is your exact requirement so that i can give proper solution.
siina, 1) firstly you need to take all html content from site url using file_get_contents. 2) Then find all image tags from html source using preg_match_all. 3) have a loop of images array and again use file_get_contents function to grab image source and save it in your folder.
if (isset($_POST['submit'])) // when form is submitted
{
if($_SESSION['item']==$_POST['h1']) // if "h1" input's value is same as item stored in session (2*: see below)
{
$_SESSION['qty'] = $_SESSION['qty'] + 1; // then increament qty stored in session
}
else // if h1's value is not matching with session (1*: see below)
{
$_SESSION['item'] = $_POST['h1']; // then save "h1"'s value in item session
$_SESSION['price']= $_POST['h2']; // save "h2"'s value in price session
}
// below is setting session array
$_SESSION['itemname'][$_SESSION['item']] = $_SESSION['item'];
$_SESSION['itemqty'][$_SESSION['item']] = $_SESSION['qty'];
$_SESSION['itemprice'][$_SESSION['item']] = $_SESSION['price'];
}
If this is related to cart then below is the meaning: 1*: if you are first time adding product to cart then it will create session 2*: if item is already in cart then increament item's quantity.
Normally there are two used of functions. 1) Just call function abstractly, and you don't need anything from function. e.g.
function echoSum($a,$b)
{
$c = ($a+$b);
echo "Sum is :".$c;
}
//==== some php code =====
echoSum($a,$b) // function output is not required further
//==== some php code =====
Here you are just adding both values and echo it in function. in your further code you are not bothered about function result.
2) Call function and you want to use outcome of function in further code. e.g.
function getSum($a,$b)
{
$c = ($a+$b);
return $c;
}
//==== some php code =====
$sum = getSum($a,$b);
$sum10 = $sum + 10; // use function output further
echo "Sum is :".$sum ." & Sum10 is :".$sum10;
//==== some php code =====
Here you are again adding two values but in further code you want to use outcome of function. Your next code will depend on function result or output.
I din't find delete link on update_user.php. If you are deleting through URL like delete_user.php?User_id=<?php echo $id ?> then it will work or post your code where you have delete link.
of-course $User_id is needed. I said $User_id = $_POST; should be $User_id = $_POST;. In form you have all fields which will be posted when you click on submit. But there is no field called User_id so you want get it in posted value. Add below code in form so User_id will be posted after submission.
I think you are passing null to "GetSQLValueString" function. Debug your code. Add below form when form is submitted. Which will show all form posted variable.
You can not use $ after bracker. $_GET; should be $_GET; Are you sure you are getting $User_id ?? Also as i said in previous page you need to define all variable before using it in update query as shown below.
<?php
if (isset($_POST['submit'])){
//if (isset($_POST['User_level'])){
$link = mysql_connect("localhost","root","root") or die ("Could not connect to the Database Server!");
$db = mysql_select_db("pqs", $link) or die ("Could not select Database!");
$User_id = $_GET['User_id'];
$User_tcno = $_POST['User_tcno'];
$User_name = $_POST['User_name'];
$User_dep = $_POST['User_dep'];
$User_username = $_POST['User_username'];
$User_password = $_POST['User_password'];
$User_level = $_POST['User_level'];
$result = mysql_query("UPDATE userdb SET User_tcno = '$User_tcno', User_name = '$User_name', User_dep = '$User_dep', User_username = '$User_username', User_password = '$User_password', User_level = '$User_level' WHERE User_id = '$User_id'");
}
if($result){
echo "<script type='text/javascript'>window.location='index.php?page=list_user.php'</script>";
}
mysql_close($link);
?>
Don't use $_POST for file input field. You need to use $_FILES for file name. and store that name in database. When you want to display image fetch filename from database and concate with $target_path. e.g. <img src="<?php echo $target_path.$file_name;?>" />
Where is $User_id defined in update_user1.php? Also you need to assign all form's posted variables. e.g. $User_tcno = $_POST; Then only you can use $User_tcno in update query.
I am using jqPrint from here : http://plugins.jquery.com/project/jqPrint Demo will not work but download file and try it. You just need to use any selector. i.g. div id.
1) If code_block.php is in parent folder then only use include('../code_block.php') if both files are at same folder then use include('code_block.php') 2) You need to create $code_block variable in code_block.php in order to use it in page.php
<? $code_block = 'html html...
but here i need an include
html html...
and here i need an include
html html...';
?>
Is the code you have posted here for gallery.inc.php is in any function? Or it is outside? If its inside you need to make it global. Generally i am always defining configuration variables. e.g. define('SQL_HOST','localhost'); so that i can use it any where inside function.
$text = "this is description...this is description...this is descr[youtubeee]http://www.youtube1...[/youtubeee]iption...this is description...this is description...[youtubeee]http://www.youtube-two...[/youtubeee]this is description...this is description...this is description...this is description...this is description...this is description...";
preg_match_all ("/\[youtubeee\]([^`]*?)\[\/youtubeee\]/", $text, $output,PREG_OFFSET_CAPTURE);
echo '<pre>';
print_r($output);
in array you will have offset, once you done with urlencode replace main string back using offset.
You are fetching images based on categoryid passed in link viewproduct_by_category.php?categoryid=1. So when you click next link url should also have categoryid i.e. viewproduct_by_category.php?categoryid=1&page=2. Check in your coding whether you are getting it or not.
