manually run your query in mysql and then see what result it displays, and share it
baig772 19 Web Application Architect
baig772 19 Web Application Architect
pritaeas commented: Thanks for sharing. +14
manually run your query in mysql and then see what result it displays, and share it
Solved it
ImageView play = (ImageView)findViewById(R.id.play2);
play.setOnClickListener(new OnClickListener() {
my Kalma2.xml did not contain any id image with id "play2". Now its running fine
i am new to android. While i am running my application, it is running well in landscape mode, but in portrait mode, application is forcefully closed giving the following in log
05-31 16:48:30.958: W/KeyCharacterMap(428): No keyboard for id 0
05-31 16:48:30.958: W/KeyCharacterMap(428): Using default keymap: /system/usr/keychars/qwerty.kcm.bin
05-31 16:50:45.728: D/AndroidRuntime(484): Shutting down VM
05-31 16:50:45.728: W/dalvikvm(484): threadid=1: thread exiting with uncaught exception (group=0x4001d800)
05-31 16:50:45.758: E/AndroidRuntime(484): FATAL EXCEPTION: main
05-31 16:50:45.758: E/AndroidRuntime(484): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.kalmas/com.kalmas.Kalma2}: java.lang.NullPointerException
05-31 16:50:45.758: E/AndroidRuntime(484): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2663)
05-31 16:50:45.758: E/AndroidRuntime(484): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2679)
05-31 16:50:45.758: E/AndroidRuntime(484): at android.app.ActivityThread.access$2300(ActivityThread.java:125)
05-31 16:50:45.758: E/AndroidRuntime(484): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:2033)
05-31 16:50:45.758: E/AndroidRuntime(484): at android.os.Handler.dispatchMessage(Handler.java:99)
05-31 16:50:45.758: E/AndroidRuntime(484): at android.os.Looper.loop(Looper.java:123)
05-31 16:50:45.758: E/AndroidRuntime(484): at android.app.ActivityThread.main(ActivityThread.java:4627)
05-31 16:50:45.758: E/AndroidRuntime(484): at java.lang.reflect.Method.invokeNative(Native Method)
05-31 16:50:45.758: E/AndroidRuntime(484): at java.lang.reflect.Method.invoke(Method.java:521)
05-31 16:50:45.758: E/AndroidRuntime(484): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:868)
05-31 16:50:45.758: E/AndroidRuntime(484): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:626)
05-31 16:50:45.758: E/AndroidRuntime(484): at dalvik.system.NativeStart.main(Native Method)
05-31 16:50:45.758: E/AndroidRuntime(484): Caused by: java.lang.NullPointerException
05-31 16:50:45.758: E/AndroidRuntime(484): at com.kalmas.Kalma2.onCreate(Kalma2.java:52)
05-31 16:50:45.758: E/AndroidRuntime(484): at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1047)
05-31 16:50:45.758: E/AndroidRuntime(484): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2627)
05-31 16:50:45.758: E/AndroidRuntime(484): ... 11 more
05-31 16:50:48.108: I/Process(484): Sending signal. PID: 484 SIG: 9
the code of my Kalma2.java is
package com.kalmas;
import android.app.Activity;
import android.content.Intent;
import android.media.MediaPlayer;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.ImageView;
public class Kalma2 extends Activity {
public void onCreate(Bundle savedInstanceState) {
final MediaPlayer kalma2 = MediaPlayer.create(this, R.raw.kalma2);
super.onCreate(savedInstanceState);
setContentView(R.layout.kalma2);
ImageView prev2 = (ImageView)findViewById(R.id.prev2);
prev2.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
kalma2.stop();
startActivity(new Intent(Kalma2.this,Kalma1.class));
}
});
ImageView next2 = (ImageView)findViewById(R.id.next2);
next2.setOnClickListener(new OnClickListener() {
@Override
public …
M- Model is your database layer
V- View is your front end i.i. displayed to the user
C- Controller acts as an intermediatry layer between Model and View
Further you can google it
you have forgot semi-colon ';' after
case 0:
$message = "Your account is now active. you may now <a href=\"login.php\">Log In!</a>"
put the semi-colon and it will be fine
Hi all,
How i can exit from an application?
Button exit = (Button)findViewById(R.id.exit_btn);
exit.setOnClickListener(new Button.OnClickListener() {
public void onClick(View v) {
// TODO Auto-generated method stub
finish();
java.lang.System.exit(0);
}
});
this code just takes me to the last activity but i want to completely close the application
As you have used POST method in your form, you can get your data as defined by ardav
How to set OnClickListener?
my code is
package com.calculator;
import android.app.Activity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
public class CalculatorActivity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button b = (Button)findViewById(R.id.button1);
String btn_val = b.getText().toString();
EditText edit_text = (EditText)findViewById(R.id.editText1);
edit_text.setText(btn_val);
}
this code is getting the value of button id = button1 and setting it in text feild. i want to do all this work when clicked on any button e.g when clicked on 2, it should print 2 in text feild
Hi all,
i am new to android development, in fact its my first application. i am making a simple calculator. i just want to know how to get the value of a pressed button.
Any help plz
Hi all
i am working on a third party recruitment site in wordpress.
Site basically acts as intermediary between candidate and employee.
Is there any plugin to manage employees and employers in wordpress??
you can call your javascript function on change like this
<select name="drop_down" onchange="calculate()">
<option>option1</option>
</select>
where in javascript you can write a function
<script type="text/javascript">
function calculate() {
alert("hello world");
}
</script>
in old look, there was some javascrpt code given by dani web to embed in site on basis of reputation points, solved threads.
if i am not wrong then its name was member badge.
base_url method is recomended by me
like dany said, ypu must have strong OOP concepts and some other concepts like MVC and ORM to build your own framework. Its better to build a framework for PHP in PHP, but like fusebox, its the coldfusion framework and also used for PHP.
I personaly like Kohana (fork of CI). that also gives ORM approach. but it depends on your project requirements, which framework you would use :)
You can also use some framework to build your own CMS. for example we have magento that is build in Zend framework
Hi all
I was on break and just came back to Daniweb.
I saw some great changes here like texteditor and user menu on top.
I have some problems, admins please guide me
firstly i am not having any email if someone replies to articles, i have posted in and secondly in controlpanel, i am not seeing my member badge
Thanks
and congrats for the new look again :)
is it redirecting to any oter page or giving some error??
share your error also
i included my css like <link rel="stylesheet" href="css/style.css" /> but while viewing source, i am having the following source <link rel="stylesheet" href="localhost/mysite/css/style.css"; />
i have following .htaccess
RewriteEngine On
DirectoryIndex index.php
RewriteRule ^([a-zA-Z0-9_-]{3,20})/([^/]+)/([^/]+)?$ index\.php?page=$1&s=$2&o=$3 [L]
RewriteRule ^([a-zA-Z0-9_-]{3,20})/([^/]+)?$ index\.php?page=$1&s=$2 [L]
RewriteRule ^([a-zA-Z0-9_-]{3,20})/?$ index\.php?page=$1 [L]
RewriteRule ^([a-zA-Z0-9_-]{3,20})?$ index\.php?page=$1 [L]
ErrorDocument 404 /404
it displays mu url as localhost/mysite/home for first perimeter and its going fine but when my url is localhost/mysite/home/user, whole look of page is disturbed i.e. no css and image is included here can any one please help me with this?
delete from table_name where skills = '';
Code blocks are created by indenting at least 4 spaces
... and can span multiple lines
Hi all
I am trying to show a comment box under each post,
i have tried
<?php get_template_part( 'content', 'single' ); ?>
<?php comments_template( '', true ); ?>
but the comment box is still invisible
Thanks for the reply veedeoo
but my site is not static, what to do if i have some text dynamic?
Hi all
I am working on a website and the requirement is to make it in two languages i.e. icelandic and english.
just like facebook and other google, if a user selects a language, then the site is translated in that language.
I am not allowed to use google translator.
Any other way to do this in Php
Thanks in advance :)
Thanks to all
Solved my problem :)
Hi all
I have following table structure
pk_cat_id(int) cat_name(varchar) cat_desc(text) fk_cat_id(int)
table is self related as one to many
i want to select cat_name, cat_desc and parent_cat_name()
i.e.
from fk_cat_id, how i can get cat_name
wow it looks great,
where i should use it?? :)
can you see name=himanshu if you put echo statement outside the while loop??
best of luck super duper :)
its obvious you cannot, because you are echoing $branch in name tag :)
share your form also
on update, it depends which table information you are updating, while deleting, both table should have cascade
options are available in phpmyadmin for altering the table i.e. look for operations tab
without looking at your code, check if you have properly redirecting the page
if(login_condition_is_true){header('location:admin_home.php')}
yes, i mean fields in text area cannot be shown, after inserted one data, when i try to edit the data, only fields in text area cannot be shown..
then most probably your selection from db is not right
it means that your form is not posted on that page
still cannot shows :(
is your question is
text area is shown but no value in it???
it seems ok
have you included your connection file correctly?
no not like this :s
type this in your form
<form action='new_ticket.php' method='post'>
and then on new_ticket.php page
type this
echo "<pre>";
print_r($_POST);
exit;
and then submit your form and share what you get
just put that php code in your form, it should work fine unless and until there is any db or syntax error
Hello, any body can help me, i've try to show field textarea, but can't.. help me please.. herewith code:
<textarea type="text" name="alamat" rows="5" cols="40" value="<?php $_POST['$alamat']; ?>" /></textarea>
try
<textarea .......><?php echo $_POST['alamat'];?></textarea>
change the action of your form and on process page, type
echo "<pre>";
print_r($_POST);
exit;
and share what you get
<input type="submit">
always submits the form regardless of any javascript validation
you should try
<input type="button" on click="checkValidation()">
and then submit your form using javascript
form.submit()
function
i commented
response.close()
because i was following an old tutorial.
please change this to
response.end()
it doesn't matter if your incrementing your id or not, mysql_insert_id() always return the last inserted id
no it returns 0 if column is not auto incremented
where you are listing hyperlinks, you can try this
www.daniweb.com/<?php echo $user_name;?>
this will take you to user profile page for each user
i guess that your scenario is that you are updating 2nd table after inserting in 1st table???
try
mysql_info()
../
means go back,
if in the same directory, then
directory1/directory2/...../file
try this
include_once('action/Upload.php');
it worked,
i changed my code to this
var sys = require("util"),
http = require("http");
http.createServer(function(request, response) {
response.writeHead(200, {"Content-Type": "text/html"});
response.write("Hello World!");
//response.close();
}).listen(8090);
sys.puts("Server running at http://localhost:8090/");