A spindle is formed by revolving the region bounded by the graphs of

y= (1/4)*[1+2e^(-x/8) *sin^(2) *((Pi*x)/4)], y=0,x=0,x=8.

About the x-axis. Determine the volume of the spindle.

Please show me how to do this?

enrichedd 0 Newbie Poster

A spindle is formed by revolving the region bounded by the graphs of

y= (1/4)*[1+2e^(-x/8) *sin^(2) *((Pi*x)/4)], y=0,x=0,x=8.

About the x-axis. Determine the volume of the spindle.

Please show me how to do this?

mrnutty 761 Senior Poster

To determine the volume you use this formula general volume formule

where:

h = any dimension of the figure,

A(h) = area of the cross-sections perpendicular to h described as a function of the position along h. a and b are the limits of integration for the volumetric sweep.

(This will work for any figure if its cross-sectional area can be determined from h).

check wiki for more info. What are you having problem with? The formation of the integral?

Rashakil Fol 978 Super Senior Demiposter Team Colleague

> sin^(2) *((Pi*x)/4)

Lolwut?

mrnutty 761 Senior Poster

Be a part of the DaniWeb community

We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.