little help about arrays

[meirre]

troubled about this:
i need help on how can i display the number of times a value appear in array

ex:
number[3][3]={{1,2,3},{2,3,4},{3,4,5}}

1 appeared 1 time(s)
2 appeared 2 time(s)
4 appeared 2 time(s)

simple tips would do....thanks

[Dave Sinkula]

One way:

#include <stdio.h>
 
 int main()
 {
    int number[3][3] = { {1,2,3}, {2,3,4}, {3,4,5} };
    struct
    {
 	  int value, times;
    } result [ sizeof number / sizeof **number ] = {0};
    size_t i, j, k;
    for ( i = 0; i < sizeof number / sizeof *number; ++i )
    {
 	  for ( j = 0; j < sizeof *number / sizeof **number; ++j )
 	  {
 		 for ( k = 0; k < sizeof result / sizeof *result; ++k )
 		 {
 			if ( number[i][j] == result[k].value )
 			{
 			   result[k].times++;
 			   goto next;
 			}
 		 }
 		 if ( k == sizeof result / sizeof *result ) /* not found -- new entry */
 		 {
 			for ( k = 0; k < sizeof result / sizeof *result; ++k )
 			{
 			   if ( !result[k].value )
 			   {
 				  result[k].value = number[i][j];
 				  result[k].times++;
 				  break;
 			   }
 			}
 		 }
 	  next:
 		 ;
 	  }
    }
    for ( k = 0; k < sizeof result / sizeof *result; ++k )
    {
 	  if ( result[k].value )
 	  {
 		 printf("%d appeared %d time(s)\n", result[k].value, result[k].times);
 	  }
    }
    return 0;
 }
 
 /* my output
 1 appeared 1 time(s)
 2 appeared 2 time(s)
 3 appeared 3 time(s)
 4 appeared 2 time(s)
 5 appeared 1 time(s)
 */

Post your own attempt if you don't understand this.