Hi,
i have the following script:

#!/bin/perl -w
use strict;

$ENV{"PATH"} = ".;" . $ENV{"PATH"};

print "Revesing the history file...\n";
print reverse <> history.txt > history_rev.txt;
print "Reversing the XpressClients file\n";
print reverse <> XpressClients.txt > Xp_clients.txt;
print "Parsing the XpressClients file...\n";
require 'Clients.pl' Xp_clients.txt > clients_file.txt;

the files are located in the same dir as the script.
the problem is - when i run the script i get this error:
Bareword found where operator expected at ./Filesx_Check.pl line 24, near "<> history"
(Missing operator before history?)

i get this error with "history", "XpressClients" and "Xp_clients", i.e, every file i mention.
i tried adding the directoy to PATH but that didn't help. i even changed the files premissions to rwx, but again, to no avail.

i'm seriously frustrated.
ANY suggestion will be appreciated.
Thanks!

When you use print, you should quote strings.

print reverse <>, "history.txt > history_rev.txt\n";

On the other hand, if you are expecting perl to know those are input and output files you must not have been awake in perl class. ;)

that's the wired thing - it works fine just the way it is in my computer, but in another computer it prints the error message.

can you point me to what im doing wrong?
do i need to open the files and insert them to arrays?

No, i tried that too.
It is possible, im just not sure why it doesnt work...
How else can i tell perl these are input and output files? any idea?
Thnaks

I did a little horsing around.

I can get reverse to work with arrays:

print reverse(@array);

But, what you are trying uses standard input (<>). If you want to do that, I believe you have to run perl via command line:

perl -e 'print reverse <>' file1 file2 file3 ....

The above is taken from this page: http://www.unixguide.net/unix/perl_oneliners.shtml

To do what you want, within a perl script, may require opening files and reading them:

open(FILE_HANDLER,"/path/to/file");
my @lines = <FILE_HANDLER>;
close(FILE_HANDLER);

Hope that helps.

Hi Stylish,

You did help my and you're wright.
In order to do :
perl -e 'print reverse <>' sourcefile.txt > 'targetfile.txt'
In a perl script i need to open files.
Problem is, that oneliner (perl -e...) is faster and prints the file, as is, backwords. In perl script when i do:
print TARGET reverse <@sourcefile>; (when TARGET is the file handler)
I get the file without spaces. for example, if it was:
daniweb forums
are helpful.
It will be :
daniwebforumsarehelpful.

I'll to play with it for a while, maybe things will start working wright.
Thank you both!
To be continued...

open(IN, "/path/to/file");
open(OUT,">",'path/to/outfile');
print OUT reverse <IN>;
close(IN);
close(OUT);

The only problem is that if there is not a newline at the end of the last line of the IN file, the reversed OUT file will have the first and second lines appended together.

Reverse ("@sourcefile") - made all the difference.
Works great.
Thank KevinADC & Stylish!

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