To find the Sin value , give me a small support

[vijaysoft1]

I have a program to find the Sin value of a given value(in radian) . It is working properly , but i want a better program or can u please give me a small explanation about my code . please ...

in my program

n=2; // what is this meaning

#include<iostream.h>
#include<math.h>
#include<conio.h>


void main()
{
	float x,s=0,term,f;
	int n,k;
	cout<<"Enter the value:";
	cin>>x;
	k=x;
	x=(x*22)/(7*180);
	term = x;
	cout<<x<<"\n";
	cout<<sin(x)<<"\n";
	fabs(s-(sin(x)));
	n=2;
	while(fabs(s-sin(x))>0.0001 )
	{
		s=s+term;
		f=-(x*x)/(n*(n+1));
		term = term*f;
		n=n+2;
	}
	cout<<"Sin "<<k<<"="<<s;
	getch();


 }

Please......

[mvmalderen]

Did you actually write this code ?

[mvmalderen]

You can use the sin function from the C++ library ...
(Look here for a reference)

[ddanbe]

22/7 is a poor approximation of pi.
You are essentially calculating the series x - (x^3)/3! + (x^5)/5! - (x^7)/7! + ... that is why n=2 at start and 2 is added every time 3+2=5 5+2=7 etc.
Don't know why k=x; is needed, for use in output you could use x as well.

[siddhant3s]

>>22/7 is a poor approximation of pi.
Very right.
PI=3.14159265
22/7 =3.14285714
Your program is not doing good. What I meant to say is the aim of the program is not clear.
Moreover, you are using old headers, using void main.
Never use void main http://cppdb.blogspot.com/2009/02/should-i-use-void-main-or-int-main-or.html

I agree with Tux4life post about "Did you actually write this code ? "
As far as the Original problem is concerned sine can be easily calculated by the sin() function in cmath.
It takes radian as its measure.
Tux has already told you that.

[vijaysoft1]

Hi friends please help me to find sin value of user input ( in radian) without using sin() from math.h . please

[rudasi]

does the user enter 1 value only?

[vijaysoft1]

does the user enter 1 value only?

yes only one value