Title probably makes no sense :)
I have a single picturebox button that I will be using to open new forms. Is there a way to set a variable and then have the button open the form name included in the variable
I really dont know where to start as every variable I set can't use the .show.
I'm guessing I have to set the variable to the current object but I'm lost.
You need to create a variable that will store a reference (if that's the right terminology, I'm not a VB pro) to the form you want to show. The variable should be of type [icode]Windows.Forms.Form[/icode]. In the following example, Form2 would be the name of the form you want your … Read More
You need to create a variable that will store a reference (if that's the right terminology, I'm not a VB pro) to the form you want to show. The variable should be of type
In the following example, Form2 would be the name of the form you want your picturebox to open:
' This represents whatever variable you use to select a form. ' Obviously it would normally be set based on some other factor. Dim whichForm As Integer = 1 Private Sub PictureBox1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles PictureBox1.Click 'This variable is what you will use to reference and show the form Dim formName As Windows.Forms.Form ' I used a Select Case to choose Select Case whichForm Case 1 formName = Form2 End Select ' Make sure to check that this is actually set -- I left it out. formName.Show() End Sub
Hope that helps!
you could create an overloaded New function in your form just like
Public Sub New (byval frmName as string) 'what ever you wanna do with the name End Sub
and you call that form by doing
Dim newFrm as New Form2(myName) newForm.Show
@EvolutionFallen works great! thanks man.
Actually really simple when you get down to it, I was making it much more complex than it needed to be.
@GeekByChoice, I'll check out your suggestion too.
then please mark the thread as solved ;)
Glad to help =)
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