0

This is my code below. If i were to enter 2 3 2 3 3 5 4, i were to get
0 0's
0 1's
2 2's
3 3's
1 4's
1 5's
0 6's
0 7's
0 8's
0 9's

#include "std_lib_facilities.h"

int main()
{


int num;
vector<int> group;
vector<int> freq;

cout<<"Enter 9 numbers, single digits. \n";
   while(cin>>num)
   {
       group.push_back(num);
   }

       for(int i=0; i < group.size(); i++)
       {
          freq[group[i]]++;
       }
       for (int j=0; j < freq.size(); j++)
       {
           cout<<""<<freq[j]<<"  "<<j<<"'s. \n";

       }
       keep_window_open();





















}

Edited by Dani: Formatting fixed

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Last Post by Grn Xtrm
0

Something like this :

vector<short> cntr(10,0); // 0 through 10 elements initialize to 0
vector<short> value(10,0); // same as above;

for(int i = 0; i < value.size(); i++)
    cin >> value[i];

//then you know the value is between the  ranges of 0 to 9, and realize
//that when user enter a number it will match the index, so.

for(int i = 0; i < value.size(); i++)
     cntr[ value[i] ] += 1;

//Then print it out.
0

thank you for your help the program works, but i was wondering if you could explain to me the for loop parts so that I can understand what is going on if you would be so kind?

0

The first for loop accepts the user input integers and adds them to the vector. The second for loop adds up the number of individual integers in the vector.

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