Hi everyone,

I'm trying to write a script that will list all files and their details within a directory - so for example, if I have the structure

/home/
/home/folder1/
/home/folder2/
/home/folder3/

It will print something like
+----------------------------
| /home/folder1/
+----------------------------
| *files here* | *size*
+----------------------------
| /home/folder2
+----------------------------
| *files here* | *size*


Although I seem to be having a bit of trouble so far - it will list all the files in one go, which is not what I want, they need to be separated by directory!

Does anyone know anyw way of doing this? I can post some code if anyone wants too take a look at it, and many thanks in advance :)

#!/bin/bash

OUTPUT=""
TAQ_FILES=""
DQR_FILES=""
TAQ_MD5=""
DQR_MD5=""

CURRENT_DIR=`pwd`

for dir in $(find $CURRENT_DIR  -type d);
do
    cd $dir
    echo "Currently Processing Files in $dir"
    OUTPUT=$OUTPUT"+-----------------------------------------------------------------------------------------------------+\n"
    OUTPUT=$OUTPUT"| TAQ Report for $dir\n"
    OUTPUT=$OUTPUT"+-----------------------------------------------------------------------------------------------------+\n"
    OUTPUT=$OUTPUT"| TAQ Files : `ls -l *.gz | wc -l` Total (`ls -l TAQ*.md5 | wc -l` md5 check sums); DQR Files : `ls -l *.txt | wc -l` Total (`ls -l DATA*.md5 | wc -l` md5 check sums) |\n"
    OUTPUT=$OUTPUT"+-----------------------------------------------------------------------------------------------------+\n"
    OUTPUT=$OUTPUT"| TAQ Files in directory\t\t\t\t\t| Size \t\t| MD5 Sum?\t\t|\n" 
    OUTPUT=$OUTPUT"+-----------------------------------------------------------------------------------------------------+\n"
    
    for file in $dir $(find -type f -iname "TAQ*.gz");
    do
        if [ $dir == $CURRENT_DIR ];
        then
        #    echo "home"
        #else
            TAQ_FILES=$TAQ_FILES"| `basename $file .csv.gz`\t\t\t\t| `ls -lh $file | awk '{print $5}'`\t\t|\n"
            if [ -e `basename $file .csv.gz`.md5  ];
            then
                echo `basename $file .csv.gz`.md5
                echo "md5 exists for $file"
            fi
        fi
    done
    
    OUTPUT=$OUTPUT$TAQ_FILES
    OUTPUT=$OUTPUT"+-----------------------------------------------------------------------------------------------------+\n"
    
    for file in $dir $(find -type f -iname "DATA*.txt");
    do
        if [ $dir == $CURRENT_DIR ];
        then
        #    echo "home"
        #else
            DQR_FILES=$DQR_FILES"| `basename $file .txt`\t\t\t\t| `ls -lh $file | awk '{print $5}'`\t\t|\n"
            # if [];
            # then

            # fi
        fi
    done
    
    OUTPUT=$OUTPUT$DQR_FILES
    OUTPUT=$OUTPUT"+-----------------------------------------------------------------------------------------------------+\n"
    
    DQR_FILES="" 
    TAQ_FILES=""
    
    echo -e $OUTPUT >> test.txt
done

How about:

#!/bin/bash
if [ $# -eq 0 ]; then
echo "You must supply a base directory to seach."
echo "usage: myscript <dir>"
exit 0
fi
ls -laR $1

or simply
ls -laR /home

I kind of like find for this because if "all" isn't exactly right, it is easy to tune.

find $basedir -print

or if you want a lot of detail:

find $basedir -ls
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