Allocating an array of int or char using malloc

Yes, you can use malloc() to allocate a simulated array of int or char. What were you trying to do that prompted this question?

no, what i am tryong to ask is that if there is an array of

char s[100]={0};


s=malloc(sizeof(char)*20);

is it valid to do so ? But why is it valid ? because s is an array already.

is it valid to do so ?

No, it's not valid. Arrays are not pointers, they're arrays. You can use malloc() and a pointer to fake an array, but it's not natively an array. Likewise, in many cases an array will be converted into a pointer, but it's not natively a pointer.

but in initial post, u said u can so ? why ?

but in initial post, u said u can so ? why ?

Obviously I didn't understand your question.

:'( sir, if i allocate memory to a pointer and make it an array , then is it now an array ? means it is just same like an array ?

if i allocate memory to a pointer and make it an array , then is it now an array ?

No, but it can largely be used to simulate an array.

what simulate means here ?

It's a fake. It acts like an array for the most part, but isn't an array. Have you considered looking up the definition of "simulate"? That's exactly what it means here.

Can you reply on my thread "request to daniweb members" ? it's a request. If you ill do, that will motivate others. thanks