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Earlier today, I was very bored. I set out to see if I could write a program that would solve 24 problems (see Wikipedia).

Now, I was bored, mind you, and I thought, "Can I solve it in 1 line of code?"

NOTE: I do not recomend this approach, it is not performant, readable, maintainable, or scalable, but it was fun.

```
using System;
using System.Collections.Generic;
using System.Linq;
namespace Linq24Solver
{
class Program
{
private static Dictionary<string, Func<double, double, double>> ops
= new Dictionary<string, Func<double, double, double>>()
{
{"+", (num1, num2) => num1 + num2},
{"-", (num1, num2) => num1 - num2},
{"*", (num1, num2) => num1 * num2},
{"/", (num1, num2) => num1 / num2},
{"^", (num1, num2) => Math.Pow(num1, num2)}
};
static void Main(string[] args)
{
while (true)
{
Console.Write("Enter 4 numbers, separated by spaces: ");
var enteredText = Console.ReadLine();
if (enteredText.Contains('q'))
break;
var splitStrings = enteredText.Split(' ');
if (splitStrings.Length != 4)
continue;
var ints = new List<double>();
foreach (var numString in splitStrings)
{
int i;
if (!int.TryParse(numString, out i))
break;
ints.Add(i);
}
if (ints.Count != 4)
continue;
var solutions = ops.SelectMany(op1 => ops
.SelectMany(op2 => ops
.Select(op3 => new { op1, op2, op3 })))
.SelectMany(oc => ints
.SelectMany((a, i) => ints
.SelectMany((b, j) => ints
.SelectMany((c, k) => ints
.Select((d, l) => new { a, b, c, d, i, j, k, l }))))
.Where(x => x.i != x.j && x.i != x.k && x.i != x.l
&& x.j != x.k && x.j != x.l && x.k != x.l)
.Select(ns => new { ns.a, ns.b, ns.c, ns.d, oc.op1, oc.op2, oc.op3 }))
.Where(x =>
x.op3.Value(x.op2.Value(x.op1.Value(x.a, x.b), x.c), x.d) == 24)
.Select(x => String.Format("{0} {1} {2} {3} {4} {5} {6} = 24",
x.a, x.op1.Key, x.b, x.op2.Key, x.c, x.op3.Key, x.d))
.Distinct();
foreach (var line in solutions)
{
Console.WriteLine(line);
};
}
}
}
}
```

Now, this doesn't produce results that work if you consider orders of operations, i.e. "1 + 3 * 6 / 1" means "add three to one, multiply that by 6, and then divide that by 1."

Also, this doesn't generate solutions with parentheses like (8/(3-(8/3))=24, but I'm working on it.