I'm working on a program with menus, but I don't know how to clear the screen before displaying the next menu.

if its just in the dos screen

#include <iostream>
#include <cstdlib>

using namespace std;

int main()
cout << "Hello World!" << endl;
cout << "End of program";
return 0;

you can put any dos command in the quotes... but make sure you include cstdlib

nope clearing a terminal window is hadnled by the operating system's kernal, exclusively.

actually there is a way around that... you could cout a bunch of back spaces...

cout << "\b\b\b\b\b\b";

or you could cout the ascii equivilent;)

Yea u can...backspaces need to b calculated...however thers a simple approach to the problem
jus print the required number of newline chars i.e '\n'
use the following code:
for(int i=1;i<26;i++)

if ur program works on a loop structure then i'd suggest using the system("clear") option (Linux) or system("cls") for Windows

hey i tried to clear screen using "conio.h> but it doesnt work then i tried again using
<process.h> or <windows.h> and it work good .. :D

Actually the <conio,h> works....atleast if u use "void main()"
N you shud add the "clrscr();" after the opening braces....(but not towards the end...as ur result will get wiped out before being 'outputted')

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