Convert string to to HEX

[sgriffiths]

Hello

how would i go about converting a string value to HEX

ie

char name[10]="STEPHEN";

Convert name to HEX

[WolfPack]

You can pass character by character to itoa with radix 16.
If you only want to display the hex values, you can use printf with format specifiers %x or %X.

[sgriffiths]

You can pass character by character to itoa with radix 16.
If you only want to display the hex values, you can use printf with format specifiers %x or %X.

I understand how to use the itoa function, but this radix 16?

Regards

[WolfPack]

If you use the radix 10, you will get a string of the an integer in base 10.
For radix 16, you will get a hexadecimal string.
You can try the example in the given web page or the one below.
e.g

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main()
{
	char name[10]="stephen";
	char buffer[21]="";
	char *pbuffer = buffer;
	int len = strlen( name );
	for( int i = 0; i < len ;i++ )
	{
		itoa (name[i],pbuffer,16);
		pbuffer +=2;
	};
	printf( "%s\n", buffer );
    return 0;
}

[sgriffiths]

When i try to compile, i get this

> gcc string_to_hex.c

Undefined first referenced
symbol in file
itoa /tmp/cc21JKaJ.o
ld: fatal: Symbol referencing errors. No output written to a.out
collect2: ld returned 1 exit status

[WolfPack]

Looks like a linker error. Do you have this problem for my example only or for the example given in the link I posted also?

[sgriffiths]

Looks like a linker error. Do you have this problem for my example only or for the example given in the link I posted also?

I cant see no given web page, but i changed the code a little to make it as simple as possible with the same error

[WolfPack]

I cant see no given web page,

I mean this web page.

[andor]

When i try to compile, i get this

> gcc string_to_hex.c

Undefined first referenced
symbol in file
itoa /tmp/cc21JKaJ.o
ld: fatal: Symbol referencing errors. No output written to a.out
collect2: ld returned 1 exit status

Yes of course itoa is nonstandard. U can implement your own itoa
http://www.daniweb.com/techtalkforums/showthread.php?t=11049&highlight=itoa
or use this code

#include <stdio.h>
#include <string.h>
int main()
{
	char name[10]="STEPHEN";
	char buffer[21]="";
	char *pbuffer = buffer;
	int len = strlen( name );
	int i;
	for(i = 0; i < len ;i++ )
	{
		sprintf(pbuffer, "%x", name[i]);
		pbuffer +=2;
	}
	printf( "%s\n", buffer );
    return 0;
}

Compiled with gcc

[WaltP]

What are you guys taking about? The original request is:

how would i go about converting a string value to HEX
ie
char name[10]="STEPHEN";

Convert name to HEX

What does this mean?
1) "STEPHEN" is not a number so it can't be converted to Hex
or
2) "STEPHEN" is a string of characters that each have a Hex value. Do you mean add these characters to get a value?

Maybe an actual example would be in order. After the conversion, what should the Hex value of "STEPHEN" be?

[sgriffiths]

How would i be able to let the user enter HEX and convert it into string?

ie

User Enters 4c3258
and displays L2X

[andor]

How would i be able to let the user enter HEX and convert it into string?

ie

User Enters 4c3258
and displays L2X

#include <stdio.h>

int main()
{
   int hex;
   
   printf("Enter hex: ");
   
   scanf("%x", &hex);
   
   printf("%c", (char) ((hex & 0xFF000000) >> 24));
   printf("%c", (char) ((hex & 0xFF0000) >> 16));
   printf("%c", (char) ((hex & 0xFF00) >> 8));
   printf("%c", (char) (hex & 0xFF));
   return 0;
}

[sgriffiths]

How could i use this in a loop, i cant get it to work

The string the user enters has to start as a character string

[Dave Sinkula]

How would i be able to let the user enter HEX and convert it into string?

ie

User Enters 4c3258
and displays L2X

Perhaps something like this.

#include <stdio.h>

int main(void)
{
   char name[10] = "4c3258", *ptr = name;
   int  i;
   while ( sscanf(ptr, "%2x", &i) == 1 )
   {
      putchar(i);
      ptr += 2;
   }
   putchar('\n');
   return 0;
}

/* my output
L2X
*/

[WaltP]

Set up a loop that takes 2 characters at a time, convert those 2 characters to a hex value, and output as a character.

To convert 2 chars to hex:

subtract '0' from first giving X. It's now binary.
if X > 9, subract 7 -- it's now hex.

Do the same with 2nd character, making Y

HEX = (X << 4) | Y which shifts the second 'digit' X by 4 bits (multiply by 16), then adds in the first 'digit'

putchar(HEX) outputs the character.

[Dave Sinkula]

Set up a loop that takes 2 characters at a time, convert those 2 characters to a hex value, and output as a character.

Didn't I do that -- and in a standard and simpler way?
:p

[sgriffiths]

????

[Dave Sinkula]

????

You have my vote for the most useless post of the year.

[sgriffiths]

Im not quite there, and need a little bit more help, when i run my code, update_record="4c3333"
i get L3^C out.....anyone help ,me so i can get the correct L33.

int Convert_Update_From_Hex(char *update_record, char *field_name )
{
    int i,k=0;
    char *pconvert=update_record;
    char converted_string[20];
 
    while(sscanf(pconvert, "%2x", &i ) == 1 )
    { 
        converted_string[k]=i;
        k++;
        pconvert +=2;
    }
 
    strcpy(update_record,converted_string);

[Dave Sinkula]

Null terminate converted_string to use it correctly with strcpy .

[sgriffiths]

Okay, i have now NULL termainted my converted_string, but this still does not work, any help?

[LEFT]int Convert_Update_From_Hex(char *update_record, char *field_name )
{
    int i, k=0;
    char *pconvert=update_record;
    char converted_string[20];[/LEFT]
 
[LEFT]    while(sscanf(pconvert, "%2x", &i ) == 1 )
    { 
        converted_string[k]=i;
        k++;
        pconvert +=2;
    }
    converted_string[k]=NULL;[/LEFT]
 
[LEFT]    strcpy(update_record,converted_string);[/LEFT]

[sgriffiths]

An additional question

If i want to convert hex 4c4c

Do i pass the complete string of 4c4c or do i pass 2 characters at a time, ie 4c, let the conversion take place to L, then pass the next 4c and let the conversion take place?

[Dave Sinkula]

Okay, i have now NULL termainted my converted_string, but this still does not work, any help?

Well, it does work, even though you did this

converted_string[k]=NULL;

instead of this

converted_string[k]='\0'; /* null terminate */

So I guess you'd have to provide more context.

Do i pass the complete string of 4c4c or do i pass 2 characters at a time, ie 4c, let the conversion take place to L, then pass the next 4c and let the conversion take place?

The function will handle a larger string, but if you want to make more work for yourself you could pass only 2 characters at a time.