I have a question:

I create a file named "number.inp". This file has a row of numbers:

5 4 4 3 3 3 2

note: 5 is the first number, haven't any space or char in front of 5

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
main()
{clrscr();
 int ch,v[10],count=0,i=0,j=1,n=0,a[10];
 FILE *f;
 f=fopen("number.inp","r");
 if(ch!=' ')
 while((ch=getc(f))!=EOF)
 {i++;
  fscanf(f,"%d",&v[i]);
  count++;
 }
 printf("file has %d numbers\n",count);
 printf("the first number is %d \n",v[1]);

  for(i=1;i<=count;i++)
 if(v[i]!=v[i+1])
 {a[j]=v[i]; j++;n++;
 }
 printf("file has %d different chars \n",n);
 for(j=1;j<=n;j++)
 printf(" %2d",a[j]);

 getch();
 fclose(f);

}

output of these code is:

file has 6 numbers
the first number is 4
file has 3 different chars:
4 3 2

the question is:

why doesn't have 7 numbers but 6 numbers

why the first number is 4 not 5

why doesn't have 4 different numbers(5 4 3 2) but 3 different numbers (4 3 2)

I think the first 2 chars is ignored.If I change the content of file named: "number.inp" to:

5 4 4 3 3 3 2

note: have a space in front of 5

this time the result is OK:

file has 7 numbers
the first number is 5
file has 4 different numbers:
5 4 3 2

thanks! :o

while((ch=getc(f))!=EOF)
 {i++;
  fscanf(f,"%d",&v[i]);
  count++;
 }

The above is reading the file twice -- the byte read by getc() is tossed into the bit bucket.. Better algorithm is

i = 0;
while(i < 10 && fscanf(f,"%d",&v[i]) > 0)
{
  i++;
  count++;
 }

I try but my program is not OK. The result is same as before. It is not change anything

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