:?: can anyone explain to me a simple way to get the lowest input and the highest input From
multiple inputs
while also counting how many are below a certain value and avove a certain value
I am at my witts end tryng to learn. I am a newbie at programming and trying so many ways that I know are unneeded so far I have this

``````#include <iostream.h>
main()
{
int totalCalls,callcounter,Duration;
int longest, shortest;
double average ;

while(callcounter <= 10) //using ten as the  amount o call to easy use
{
cout << "Enter Call duration  :\n"; \\ lenght of calls
cin   >> Duration ;\\ user input

totalcalls = totalcalls + duration;\\ adds duration to call total
callcounter+ ; \\add one or every loop to counter

}//end while

average = totalcalls/callcounter;\\ average of all calls
if (duration ==5)
shortest = duration

cout << " Average length of all calls :"<< average <<"\n";
cout << " Total length of all calls  :"<< totalcalls<<"\n";
cout << " Total of call\t :"<< callcounter<<"\n";
}endmain``````

I can't seem to get the hang of getting the maximum legnth of calls and the miniumun length of calls also calls below and above a certain number
I have tried multiple if statements but am lost
I know it may be possible that I have to use arrays, switchs or a pointers
but as I have just started to learn C++ within the last two weeks any help is appreciated

< :?: If it aint hard it it good >

## All 5 Replies

this function get the minimum value for numbers that the user will input

#include<iostream.h>
using namespace std;
int min(const in *Numbers, const int Count)
{
int Minimum = Numbers[0];
for(int i = 0; i < Count; i++)
Minimum = Numbers;
return Minimum;
}
double Min(const double *Numbers, const int Count)
{
double Minimum = Numbers[0];
for(int i = 0; i < Count; i++)
if( Minimum > Numbers )
Minimum = Numbers;
return Minimum;
}
double Min(const double *Numbers, const int Count)
{
double Minimum = Numbers[0];
for(int i = 0; i < Count; i++)
if( Minimum > Numbers )
Minimum = Numbers;
return Minimum;
}
int main()
{
int Nbrs[] = { 12, 483, 748, 35, 478 };
int Total = sizeof(Nbrs) / sizeof(int);
int Minimum = Min(Nbrs, Total);
cout << "Minimum: " << Minimum << endl;
return 0;
}

Here is an example of running the program:
Minimum: 12Press any key to continue

Hmm how about declaring 2 macros:

``````#define max(a,b) a>b?a:b
#define min(a,b) a<b?a:b
int max,int min;
...
max=max(x[0],x[1]);
min=min(x[0],x[1]);
for (i=2;i<n;i++)
{
max=max(max,x[i]);
min=min(min,x[i]);
}
...``````

I hope it's write since I didn't test it. :o

whoa there now I appreciate the help

that macro was a lil bit above my head
but I will look into that also meab thanks for the post
with maxnum function

I found something that was more simple to use

``````for (j=0;j >= 100 ;j++)
counter++
``````

this way I can keep count of all my inputs and determine the max and min

I think , But thanks to all who have contributed

<if it aint hard it aint right >

:lol: ok I have tried your way and and now I understand what you mean
it was basically the same :lol:

if it aint hard it aint right

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