How do I delete the last character of a string

[shoebodh]

I am a beginner in VB. I am trying to make a simple unit converter. Can please some body tell me how can I delete the last character of the number I enter in my inputbox?

thank you

Take input as a string. Chop of the last character, then convert string to number.

[waynespangler]

I assume you are putting your input to a textbox. So try this:

TextBox1.Text = InputBox("Enter number")
        TextBox1.Text = TextBox1.Text.Substring(0, TextBox1.Text.Length - 1)

[SolTec]

I am a beginner in VB. I am trying to make a simple unit converter. Can please some body tell me how can I delete the last character of the number I enter in my inputbox?

thank you

You also could use the IsNumeric(TextboxName.Text) Then
TextboxName.Text.Length -1 as the other poster stated which will subtract the last number in the textbox

[Ramy Mahrous]

Dim str As string 
str = "Ramy1"
str = str.Remove(str.Length - 1);
' str = Ramy

[Jx_Man]

i think wayne already answered this thread. :D

[Ramy Mahrous]

Yes yes thanks JX :D

[dhanalakahmi s]

I need to remove the last ",-1,-1,-1" from this line

'XXXXXX XXXX `XXXXXXXXXXXX` XXXXX (XXXX,'XX','XXXX','YYYY YYY YYYYYY YYYYY YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY YYYYYYYYYYYYYYYYYYY.',Y,'YYYYY YY YYYY YYY YYYY XX.XX',X,X,-1,-1,-1)'

[Reverend Jim]

Is that a specific example of a more general case?. For example, if the last three fields are always -1,-1,-1 then you just need to replace ",-1,-1,-1)" with ")". However, if the last three fields can take on other values then one solution would be a loop that would look for the last "," and strip off the last field. You could do (for example):

Private Function StripLast(ByVal flds As String, ByVal numflds As Integer) As String

	Do While numflds > 0
		flds = flds.Substring(0, flds.LastIndexOf(","))
		numflds -= 1
	Loop

	Return flds & ")"

End Function

will return the string with the last given number of fields stripped off. Sample call is:

flds = "YYYYYYYYYYYYYYYYYYY.',Y,'YYYYY YY YYYY YYY YYYY XX.XX',X,X,-1,-1,-1)"
flds = StripLast(flds,3)

'flds now has the value "YYYYYYYYYYYYYYYYYYY.',Y,'YYYYY YY YYYY YYY YYYY XX.XX',X,X)"

Is this what you intended?

[Davinder Singh]

$string = "Hello Daniweb1234";
$string= substr_replace($string ,"",-4);
echo $string;

--display--
Hello Daniweb

[Reverend Jim]

1. This thread is old. Don't revive it.
2. Your answer has nothing to do with the question.
3. Your code isn't VB code.