If this fails, please try one more time of hardcoding it with the following statement:

"SELECT * FROM Addresses WHERE Zip LIKE '91%'"

And let me know if that returns anything as well.

Hi guys

I did some googling and tried to find out things about wildcards.

It might work (just might) if changing this wildcard (%) to this wildcard (*). Depends on what database in use. Some "sources" says that this one is for Access and the (%) is SQL servers. I don't now for sure but it is worth trying if the last hint doesn't work.

' " & izip & " * ' "