0

hello friends,

I am try to get database values from while loop. but It gives me

Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/empower.md/www/index_ujbee_file_uploard.php on line 32

here this is my code...

require "connect_ujbee_file_uploard.php";
require "todo.class_ujbee_file_uploard.php";
// Select all the todos, ordered by position:
$query = mysql_query("SELECT * FROM `ujbeeFile` ORDER BY `position` ASC");
$todos = array();
// Filling the $todos array with new ToDo objects:
while($row = mysql_fetch_assoc($query)){
	$todos[] = new ToDo($row);
}

but this is perfectly working at my local machine.I am using XAMPP version 2.5.8 but I put this script in to real server it give that error massage.

anybody can help me...? please....

Thank you
Umanda Jayo bandara

4
Contributors
4
Replies
5
Views
7 Years
Discussion Span
Last Post by rajarajan07
0

Change line 4 into:

$query = mysql_query("SELECT * FROM `ujbeeFile` ORDER BY `position` ASC") or die(mysql_error());

You will see that you do not have rights to login, the database does not exist, the table does not exist, or there is an error in your query.

0

try this.

$database = '';
$conn = mysql_pconnect(...conn info...);
mysql_select_db($database, $conn);
$query = "SELECT * FROM `ujbeeFile` ORDER BY `position` ASC";
$sql = mysql_query($query, $conn) or die(mysql_error());
while($row = mysql_fetch_assoc($sql)){
// the stuff
}

hope this helps :)

This question has already been answered. Start a new discussion instead.
Have something to contribute to this discussion? Please be thoughtful, detailed and courteous, and be sure to adhere to our posting rules.