Please can somebody help with this. I want a Buy Now image to go to the producturl in the database, at the moment I am just echoing , so it only shows the text of the url in the cell.
my code currently is
echo $row['ProductUrl'];
echo "</td></tr>";Hope somebody can help as it is driving me mad..... newbies hey!!!!!
Jump to PostAssuming your image is located at http://www.yoursite.com/Images/buyNow.gif, then try:
echo sprintf( '<a href="%s"><img src="%s"/></a>', $row['ProductUrl'], '/Images/buyNow.gif' ); echo "</td></tr>";
Assuming your image is located at http://www.yoursite.com/Images/buyNow.gif, then try:
echo sprintf( '<a href="%s"><img src="%s"/></a>', $row['ProductUrl'], '/Images/buyNow.gif' );
echo "</td></tr>";thanks alot that seems to have sorted it. Thanks again
You are welcome! Be sure to mark the question as solved.
Regards,
Hielo
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