Hi,
i am having problem uploading.

1.

<html>
<body>

<form action="upload_file.php" method="post"
enctype="multipart/form-data">
<label for="file">Filename:</label>
<input type="file" name="file" id="file" /> 
<br />
<input type="submit" name="submit" value="Submit" />
</form>

</body>
</html>

2.

<?php
if ($_FILES["file"]["error"] > 0)
  {
  echo "Error: " . $_FILES["file"]["error"] . "<br />";
  }
else
  {
  echo "Upload: " . $_FILES["file"]["name"] . "<br />";
  echo "Type: " . $_FILES["file"]["type"] . "<br />";
  echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
  echo "Stored in: " . $_FILES["file"]["tmp_name"];
  }
?>

3. i can browse and upload the file. But i get below screen, when i click submit.

0)

{echo "Error: " . $_FILES["file"]["error"] ."
  }
else
  {
  echo "Upload: " . $_FILES["file"]["name"] . " 
  echo "Type: " . $_FILES["file"]["type"] . "
  echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb ";
  echo "Stored in: " . $_FILES["file"]["tmp_name"];
  }

I am new. Do i need to create a folder so attached file can be saved?

Thanks.

I'm willing to talk about this to you. inside your saved where the php program and the html file was saved, you must create a folde of the name you want. and then what ever is the name of your folder is the same as the folder in the variable...

$name_of_file=$_FILES['name'];
$tmp_name=$_FILES['tmp_name'];
$path="name_of_your_created_folder/".$name_of_file
if($error==UPLOAD_ERR_OK) //checks the upload if it is ok
{
move_uploaded_file($tmp_name,$path);
}
else{
echo "upload error";
}

Thanks.

I created a folder "upload". i did not create a file inside the folder.
i had the below code. i dont get error message but i get blank scree after i click submit. then i went to folder UPLOAD but attached file was not there.

<?php
$name_of_file=$_FILES['name'];
$tmp_name=$_FILES['tmp_name'];
$path="upload/".$name_of_file
if($error==UPLOAD_ERR_OK) //checks the upload if it is ok
{
move_uploaded_file($tmp_name,$path);
}
else{
echo "upload error";
}
?>

pls ADVISE.

Colon ';' is missing at line 4. Also, try with realpath of your upload folder. Change the '$path' like below:

$path = $_SERVER['DOCUMENT_ROOT'] . "/your_web_folder/upload/" . $name_of_file;

Don't miss the colon ';' at the end of the line.

Hi,

i had the below code. i get blank screen after i hit submit. then i look in the upload folder i see nothing in there. i created upload folder. but i did not do the name of file.

$path = $_SERVER['DOCUMENT_ROOT'] . "/your_web_folder/upload/" . $name_of_file;

Should i keep $name_of_file or i should change it to something?

my code i ran:

<?php
$name_of_file=$_FILES['name'];
$tmp_name=$_FILES['tmp_name'];
$path = $_SERVER['DOCUMENT_ROOT'] . "/sqlPractice/upload/" . $name_of_file;
if($error==UPLOAD_ERR_OK) //checks the upload if it is ok
{
move_uploaded_file($tmp_name,$path);
}
else{
echo "upload error";
}
?>

Thx.

@bangla, You've incorrect variables for file.

$name_of_file=$_FILES;
$tmp_name=$_FILES;

File name array should've key as the html input file name you used, and the values follow 'name, type, size, error, tmp_name' respectively. As below example:

$file_name = $_FILES['upfile']['name'];
$file_size = $_FILES['upfile']['size'];
$file_type = $_FILES['upfile']['type'];
$temp_file = $_FILES['upfile']['tmp_name'];
$status = $_FILES['upfile']['error'];

Try with below:

<?php
$file_name=$_FILES['upfile']['name']; // give the name of HTML input file name as 'upfile'
$tmp_name=$_FILES['upfile']['tmp_name'];
$status = $_FILES['upfile']['error'];
$path = $_SERVER['DOCUMENT_ROOT'] . "/sqlPractice/upload/";
if(!is_dir($path)) {
//check the directory is already exists, otherwise, create it
mkdir($path, 755);
}
if($status==UPLOAD_ERR_OK) //checks the upload if it is ok
{
move_uploaded_file($tmp_name,$path.$file_name);
}
else{
echo "upload error";
}
?>

Your HTML should've below:

<form method="post" action="upload.php" enctype="multipart/form-data">
<input type="file" name="upfile" /><br />
<input type="submit" value="Upload" name="upload" />
</form>

Replace the file name you want to process in "action=''".

Hope this help.

1.

<form method="post" action="upload.php" enctype="multipart/form-data"><input type="file" name="upfile" /><br /><input type="submit" value="Upload" name="upload" /></form><form method="post" action="upload.php" enctype="multipart/form-data">
<input type="file" name="upfile" /><br />
<input type="submit" value="Upload" name="upload" />
</form>

2.

<?php$file_name=$_FILES['upfile']['name']; // give the name of HTML input file name as 'upfile'$tmp_name=$_FILES['upfile']['tmp_name'];$status = $_FILES['upfile']['error'];$path = $_SERVER['DOCUMENT_ROOT'] . "/sqlPractice/upload/";if(!is_dir($path)) {//check the directory is already exists, otherwise, create itmkdir($path, 755);}if($status==UPLOAD_ERR_OK) //checks the upload if it is ok{move_uploaded_file($tmp_name,$path.$file_name);}else{echo "upload error";}?><?php
$file_name=$_FILES['upfile']['name']; // give the name of HTML input file name as 'upfile'
$tmp_name=$_FILES['upfile']['tmp_name'];
$status = $_FILES['upfile']['error'];
$path = $_SERVER['DOCUMENT_ROOT'] . "/sqlPractice/upload/";
if(!is_dir($path)) {
//check the directory is already exists, otherwise, create it
mkdir($path, 755);
}
if($status==UPLOAD_ERR_OK) //checks the upload if it is ok
{
move_uploaded_file($tmp_name,$path.$file_name);
}
else{
echo "upload error";
}
?>

I had a folder upload. I did not create any file inside upload. after i attach the file, i clicked upload. i got blank screen, no error msg. then i double clicked the upload folder. nothing is inside.

Pls advise.

Actually,

#2 =

<?php
$file_name=$_FILES['upfile']['name']; // give the name of HTML input file name as upfile'

$tmp_name=$_FILES['upfile']['tmp_name'];

$status = $_FILES['upfile']['error'];

$path = $_SERVER['DOCUMENT_ROOT'] . "/sqlPractice/upload/";

if(!is_dir($path)) { //check the directory is already exists, otherwise, create it

mkdir($path, 755);

}

if($status==UPLOAD_ERR_OK) //checks the upload if it is k

{

move_uploaded_file($tmp_name,$path.$file_name);
}
else
{
echo "upload error";
}
?>