Problem querying SQLite database

Hi. I have a local installation of SQLite3 and PHP which runs a small in house PHP application so sql injection is not an issue.

I am able to execute the following:

if(isset($_GET['deletequote'])) {
    $qno = $_GET['deletequote'];
    echo $qno;?><br><?php // for testing
    $db = new SQLite3('./fi_data.db') or die('Cannot delete quote. Unable to open database');
    $delresult = $db->query("
    DELETE FROM quotes
        WHERE quote_id = '".$qno."'");
  }

The code above works correctly. However, when I execute the following no data is returned:

if(isset($_GET['editquote'])) {
    $qno = $_GET['editquote'];
    echo $qno;?><br><?php // for testing        
    $db = new SQLite3('./fi_data.db') or die('Cannot edit quote. Unable to open database');
    $results = $db->query("SELECT quote_to FROM quotes WHERE quote_id = '".$qno."'");
    while ($row = $results->fetchArray()) {
    var_dump($row);
}

I have also tried with a prepared statement which also does not return any data:

if(isset($_GET['editquote'])) {
        $qno = $_GET['editquote'];
        echo $qno;?><br><?php // for testing
        $db = new SQLite3('./fi_data.db');
        $stmt = $db->prepare('SELECT quote_to  FROM quotes WHERE quote_id = :qn');
        $stmt->bindValue(':qn',$qno);
        $results =  $stmt->execute();
        while ($row = $results->fetchArray()) {
        var_dump($row);
    }

If I remove the WHERE part of the query and use only:

'SELECT quote_to  FROM quotes'

then the expected data is returned.

Why is the first statement working but not the second one?
Can anyone spot where I've gone wrong?
Thanks in advance.

[Dani]

Maybe there are simply no rows that have the quote_id set to the value of $qno simply because your first query literally deleted all the rows that existed in the database where that was the case.

[pritaeas]

then the expected data is returned.

Show some of the returned data.

[AndrisP]

In your examples 2 and 3 are missing final } on while loop

[Dani]

In your examples 2 and 3 are missing final } on while loop

Yes, that would cause a PHP fatal error which would cause the PHP script to just not display anything.

Thanks for the help, everyone.
The error was actually whitespace generated at the end of the $qno variable.
Problem was solved by using trim($qno);