Dear All
I admit that I am new to this all.
I am trying to run a simple login function.

I have two jsp files, login.jsp and welcome.jsp and I have one servelet

My project name is onjava (I am doing this from an example from the web).
My directory structure is the following:


The contents of login.jsp are:

<html><head> <title>OnJava Demo</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"></head>    <table width="500" border="0" cellspacing="0" cellpadding="0">     <form name="loginForm" method="post" action="servlet/com.onjava.login">     <tr>      <td width="401"><div align="right">User Name: </div></td>      <td width="399"><input type="text" name="username"></td>     </tr>     <tr>      <td width="401"><div align="right">Password: </div></td>      <td width="399"><input type="password" name="password"></td>     </tr>     <tr>      <td width="401"> </td>      <td width="399"><br><input type="Submit" name="Submit"></td>     </tr>     </form>    </table></body></html>

The contents of web.xml are:

<?xml version="1.0" encoding="ISO-8859-1"?> <!DOCTYPE web-appPUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"""> <web-app>        <servlet>        <servlet-name>login</servlet-name>        <servlet-class>com.onjava.login</servlet-class>        </servlet></web-app>

When I run this small functionality, my login page shows up perfectly, but when I put in the user name and the password, the page opens up with the following message.
HTTP Status 404 - /onjava/servlet/com.onjava.login

type Status report
message /onjava/servlet/com.onjava.login
description The requested resource (/onjava/servlet/com.onjava.login) is not available.

Apache Tomcat/5.5.17
I think there is some error in the action of the login.jsp page, I have tried many path options for the servelet, but nothing is working.

Any sort of help is very much appreciated.

I think that you forgot to add <servlet-mapping> in your web.xml.



1) servlet mapping is missing as mentioned by (jfdaniel07) user
2) There is no need to mention "servlet" in the url .It may be as follows,