hey guys i just need someone to help me out in parts (c) and (d) of the following question:

a- Implement the function f(a,x)=sin(ax)/x. (the prototype is double f1(double a, double x). Note that this function is equal to a for x=0. (6 points)
b- Write a code that asks the user to enter a, and calculates the sum: sum= f(a,0)+f(a,0.01)+f(a,0.02)+…+f(a,1) , i.e. in the interval 0<=x<=1. Test your code for a=12, and include the result as a comment in your program.

c- Write a code which counts, calculates, and displays the roots of f(a,x) in the interval 0<=x<=1, with an error less than 0.01. Note that a root exists between r and r+0.01 if f(a,r)*f(a,r+0.01) is negative. Test your code for a=12, and include the result as a comment in your program.

d- Write a code which counts, calculates, and displays the number of minima of f(a,x) in the interval 0<=x<=1, with an error less than 0.01. Test your code for a=12, and include the result as a comment in your program.

do you want the code or explanation

for the (c) part you just have to write the square root code

an explanation would do

``````double SQRT(double num)

{

// Assume that the number is less than 1,000,000. so that the maximum of SQRT would be 1000.

// Lets assume the result is 1000. If you want you can increase this limit

double min = 0, max = 1000;

double test = 0;

if(num < 0)

{

printf("Negative numbers are not allowed");

return -1;

}

else if(num == 0)

return 0;

while(1)

{

test = (min + max) / 2;

{

// min needs be moved

min = test;

}

{

// max needs be moved

max = test;

}

break;

if(num > (answer - 0.01) &&