nav33n

No. It doesn't work that way with torrents. Btw, Its a taboo subject to discuss it here. :)

$result will have a result resource. You need a loop to get all the result. mysql_fetch_array() will fetch only 1 record at a time. [code=php] while($row = mysql_fetch_array($result,MYSQL_NUM)) { print "<pre>"; print_r($row); print "</pre>"; } [/code]

Nothing wrong with the script. Umm.. Check if it enters the loop, [icode]If (isset($_POST['submit'])) { [/icode]. Try mysql_error to know what exactly is the error message. ie., [code=php] $sql = mysql_query("INSERT INTO accesscarduse (SchoolName, SchoolEmail, UserName, pscode) VALUES ('$SchoolName', '$SchoolEmail', '$UserName', '$pscode')") or die (mysql_error()); [/code] Also check if error …

Nice queries.. But still, that wouldn't solve what OP is looking for.. The still doesn't return the count as 0, if a user doesn't have any posts. I created dummy tables to create the same scenario and I am also clueless ! :S

You need to mention http:// in your hyperlinks. See this for example. [code=php] <?php echo "<a href='www.google.com'>Click here </a><br />"; echo "<a href='http://www.google.com'>Click here too</a>"; ?> [/code]

Yeah, possible. Have a hidden field in the form to store the id. When the user clicks submit, update the table :) [code=mysql] update table set orderno='".$_POST['orderno']."' where id='".$_POST['id']."'"; [/code]

I guess, you don't have enough permissions on tmp directory. Give all the permissions to tmp directory and try again. When you use session_start, it will create a cookie if this option [i]session.use_cookies[/i] is turned on.

What does your query do ? Query the table 'photos' and for every photo, You are again querying the table 'ratings' if that photo's fbid has a count > 150 ? I didn't get the question or what you actually want. Do these 2 tables have any common 'linking' field …

Use [icode]$action == 'preview' [/icode] and [icode]$action=='submit' [/icode]. Also, mention Form's 'method'. If you don't mention it, I guess, the default method is GET.

Simply use double quotes. ie., [icode]$num="0024";[/icode] Adding 0 before a number forces php to consider this as a octal number. [url]http://us3.php.net/int[/url]

@cwarn23, mail function works fine in if condition. The mail function returns true on success and false on failure. It works just like, [icode]if(empty($var)) { [/icode] @OP, check your spam folder. On many occasions, mails sent using php function lands up in spam folder!

[icode]select * from database [/icode] would work just fine since you want all the records without satisfying any condition :) Btw, 'for' and 'type' are mysql reserve keywords and requires ` to be wrapped around it. like, `for`, `type`.

Posting some relevant code would help.

print "<pre>"; print_r($_POST['checkbox_element_name']; print "</pre>"; Does it print anything ? There is nothing wrong in your code except the checkbox name may be wrong :) Edit: And a thumbs up for using [code] tags in your first post You should close the tag correctly next time. :)

Btw, Java is totally different from Javascript. :)

Seems like a homework question to me! :)

Hi there! The issue is with innerHTML! Check this link.. [url]http://www.developer-x.com/content/innerhtml/[/url]

[url]http://www.daniweb.com/forums/thread177977.html[/url] Multiple threads for the same problem ? Not good.

[url=http://www.w3schools.com/htmldom/prop_text_readonly.asp] readOnly . [/url]

[quote]In the table there is no value of c and hence nothing is returned What is the value of $b?[/quote] $b will still hold a result resource. Check [i]Return values[/i] here.. [url]http://in.php.net/function.mysql-query[/url]

password column is of datatype varchar (I think). Try this. [code=php] $q="UPDATE login SET password='".SHA1('$newPassword')."' WHERE id='$loginID' AND password='".SHA1('$oldPassword')."'"; [/code]

And the title, even that doesn't make any sense.

FYI, Notice is not an error and can be turned off with different [url=http://in.php.net/manual/en/function.error-reporting.php]Error reporting [/url] values.. Edit: It is kind of an error, but can be ignored. (Doh!)

[code=php] $q="SELECT id FROM login WHERE username='$username'"; $sql=mysql_query($q); if (@mysql_num_rows($sql)==1) { $arr=mysql_fetch_array($sql); $id=$arr["id"]; } [/code] :-/

[code=mysql]select count(*) as total from user group by jobs[/code] ----------------------------- Total ------ Jobs ----------------------------- 10 ------> Unemployed 20 ------> Employed Cheers!

You can have a field in your table to store the total questions answered by the user in bit format. For example, if there are 10 questions and the user has answered 4 of it, save, 1111000000 to the table. Then, when the user logs in next time, show only …

[code=php] <?php //install2.php if(isset($_GET['unlink']) && $_GET['unlink']=="true") { unlink("install.php"); unlink("install2.php"); header("location: success.php"); } //rest of the code here echo "<a href='install2.php?unlink=true'>Click here to remove the installation files ! </a>"; ?> [/code] Works on local machine. I haven't tested it on server! If you want to do the same with a button, …

In your dblayer.php, echo [url=http://in2.php.net/getcwd]current working directory[/url]. Depending on which directory you are in, you can use [b]../[/b] to go back one step to previous directory, [b]../../[/b] to go back 2 steps and so on.. ie., If the file is in public_html/common/dblayer.php , using [b]../[/b] will take you to the …

Do you get any error ? And, you don't have session_start(); in this script :-/

You are doing it wrong.. [icode]$result = mysql_query($query);[/icode] This will execute the query and return the result resource. You have to then use mysql_fetch_array (mysql_fetch_row/mysql_fetch_assoc/mysql_fetch_object) ! Read it here.. [url]http://in.php.net/function.mysql-query[/url] [code=php] $query = "SELECT * FROM item WHERE item_id = '1'"; $result = mysql_query($query); $row = mysql_fetch_array($result); //if it returns …

When adding the data to the table, use [url=http://in.php.net/nl2br]nl2br[/url] function (if you are using php).

1. Yes. Since you know where you will be uploading the file, you can save the foldername as albumname 2. By using multiple [icode]<input type='file' >[/icode] tag I am not sure if the examples in these links work, but, this is how you do it. [url]http://www.phpeasystep.com/workshopview.php?id=2[/url] [url]http://www.plus2net.com/php_tutorial/php_multi_file_upload.php[/url]

[code=php] <?php $con = mysql_connect("localhost","root"); mysql_select_db("test"); $q = "select * from table1"; $result = mysql_query($q); $i=0; while($row = mysql_fetch_array($result)) { $result_set[$i] = $row; $i++; } for($i=0;$i<count($result_set);$i++) { print "<pre>"; if($next_element < count($result_set)-1) { $next_element = $i+1; print "Next element in the array is: <br><br>"; print_r($result_set[$next_element]); } print "Now the array …

[url]http://www.mssqlcity.com/FAQ/General/char_vs_varchar.htm[/url] Summary: If you specify column's datatype as char(20) and you enter a value, say, "test", mysql still uses 20 bytes.. But if the column's datatype is varchar, and you enter "test", it uses only 4 bytes.. The best place to use char is when you are 100% sure that …

No it wont! cwarn23 is appending a "|" after every error message. So, if there are 2 errors, the query string would look like, [quote] Name is a required field please complete and submit it again.| Please fill in a correct email address| [/quote] I personally don't prefer doing it …

Did you check the source ? [icode] $string = "<div id=\"$class\"> $words </div>"; [/icode] I just had everything in one script and it works fine. (Oh, I also replaced . with # of your css. [code=php] <?php function pop_boxes($words, $class) { $string = "<div id=\"$class\"> $words </div>"; print($string); } ?> …

You can do this in php itself ! Why do you want to rely on javascript ?

Answer is Yes to both the questions. [code=php] <html> <body> <form name='test' method='post'> <input type='text' id='name' name='name'> <input type='text' id='age' name='age'> </form> <?php $value = 1; if($value == 1) { echo "<script>document.getElementById('age').focus();</script>"; echo "<script>document.getElementById('name').disabled=true;</script></script>"; } ?> </body> </html> [/code]

[quote]and another issue: include("$path/...") ===> you are giving dynamically path to your pages, this is not secure. don't do that.[/quote] Could you please explain why ?

Do you mean this ? [url]http://www.daniweb.com/code/snippet130.html[/url]

[quote] if($filename!="NULL" || $filename!="FALSE" || $filename!="") [/quote] This must be [quote] if($filename!=NULL && $filename!=FALSE && $filename!="") [/quote] In your example, you are checking if variable filename value is NULL or FALSE (which is wrong). And, you should use logical operator "and" instead of "or".

Are you sure it doesn't work ? I downloaded the script and it works just fine! See the attached screenshot..

2 errors. 1st one is on line 30. $message = $_POST('$SchoolName',.... 2nd error, there is no ; after mail function. Please check [url=http://in.php.net/manual/en/function.mail.php] this [/url] for the correct syntax of mail function! Edit: Also, this [quote] echo "Form not properly completed") [/quote] is not terminated by a semicolon and there …

Well, thats because only the last value is stored in variable $val because of the while loop. You can 1. Put value of $row["name"]; to an array and iterate through that array in your select tag or 2. Use <option> tag in your while.

[code=mysql] update journey j, passengers p, shuttle s set j.occupancy=j.occupancy - 1 where p.journey_id = j.id and s.id = j.shuttle_id and s.id = 1 and p.passenger_name='bill gates' [/code] wouldn't this work ? Many people at my workplace avoid joins (they say its comparatively slower than normal queries).

Check mysql function [url=http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_substring-index]substring_index [/url] Eg. [code=mysql] SELECT SUBSTRING_INDEX(columnname, "\n", 10 ) FROM table [/code]

foreach($array as $value) simply means, for every element in the array, assign its value to $value. foreach($array as $key => $value) assigns the index of the array to $key and value of that index to $value. :S I hope I am not confusing you! This is almost similar to for …

Google "login form php". You will find atleast 10000 links.

[quote] i want to remove all word from that string if that string have minimal three word'x'[/quote] I am not clear what you want. Do you want to search for xxx, if found, remove it ?

While fetching, use str_replace to replace "<br />" with "". ie., [code=php] str_replace("<br />", "", $data); [/code]