Posts by <M/>

Yeah, it only gives me the decimal format for mean?

Okay, so like this:

import java.text.DecimalFormat;
import java.util.*;
public class Mean {
     public static void main(String [] args){
    Scanner s = new Scanner(System.in);
        double[]x = new double[10];
        int i;
        for(i = 0;i < 10; i++){
            x[i] = s.nextDouble();
        }
        double mean = mean(x, i);
        double deviation = var(x);
        System.out.println("The mean is " + mean); 
        DecimalFormat df = new DecimalFormat("#.##");
        System.out.println("The standard deviation is " + df.format(deviation));    
}
public static double sum(double[] a) {
        double sum = 0.0;
        for (int i = 0; i < a.length; i++) {
            sum += a[i];
        }
        return sum;
    } 
    public static double mean(double[]x, double i){ 
        if (x.length == 0) return Double.NaN;
        double sum = sum(x);
        return sum / x.length;
    } 
    public static double var(double[] x) {
if (x.length == 0) return Double.NaN;
double avg = mean(x, 10);
double sum = 0.0;
for (int i = 0; i < x.length; i++) {
    sum += (x[i] - avg) * (x[i] - avg);
}

return Math.sqrt(sum/(x.length-1));
 }
 }

but what about the decimal format for Standard Deviation?

So like this:

import java.text.DecimalFormat;
import java.util.*;
public class Mean {
    public static void main(String [] args){
        Scanner s = new Scanner(System.in);
            double[]x = new double[10];
            int i;
            for(i = 0;i < 10; i++){
                x[i] = s.nextDouble();
            }
            double mean = mean(x, i);
            double deviation = var(x);
            System.out.println("The mean is " + mean); 
            System.out.println("The standard deviation is " + deviation);
    }
public static double sum(double[] a) {
        double sum = 0.0;
        for (int i = 0; i < a.length; i++) {
            sum += a[i];
        }
        return sum;
    } 
    public static double mean(double[]x, double i){ 
        if (x.length == 0) return Double.NaN;
        double sum = sum(x);
        return sum / x.length;
    } 
    public static double var(double[] x) {
        if (x.length == 0) return Double.NaN;
        double avg = mean(x, 10);
        double sum = 0.0;
        for (int i = 0; i < x.length; i++) {
            sum += (x[i] - avg) * (x[i] - avg);
        }
        DecimalFormat myFormatter = new DecimalFormat("#,##0.00");
        return Math.sqrt(myFormatter(sum/(x.length-1)));

    }
}

@AD, not that kind of stick man! like a little sketch, lol!

Granted, you never woke up...

I wish i mastered all programming languages (don't laugh)

Well... on the bright side, anchorman 2 wasn't that great...

Hmmm... i tried your code and it said: "cannot find symbol
System.out.println("The number of integers is " + count++);"

So like this:

import java.text.DecimalFormat;
import java.util.*;
public class Mean {
    public static void main(String [] args){
        Scanner s = new Scanner(System.in);
            double[]x = new double[10];
            int i;
            for(i = 0;i < 10; i++){
                x[i] = s.nextDouble();
            }
            double mean = mean(x, i);
            double deviation = var(x);
            System.out.println("The mean is " + mean); 
            System.out.println("The standard deviation is " + deviation);
    }
public static double sum(double[] a) {
        double sum = 0.0;
        for (int i = 0; i < a.length; i++) {
            sum += a[i];
        }
        return sum;
    } 
    public static double mean(double[]x, double i){ 
        if (x.length == 0) return Double.NaN;
        double sum = sum(x);
        return sum / x.length;
    } 
    public static double var(double[] x) {
        if (x.length == 0) return Double.NaN;
        double avg = mean(x, 10);
        double sum = 0.0;
        for (int i = 0; i < x.length; i++) {
            sum += (x[i] - avg) * (x[i] - avg);
        }
        DecimalFormat myFormatter = new DecimalFormat("#,##0.00");
        return sum / myFormatter.format(Math.sqrt(sum of(squared(x - mean))/N-1));
    }
}

@dev90,

Like this:

import java.util.Scanner;
public class IntegerCount
{
public static void main(String[] args)
{
int num,count=0;
Scanner input = new Scanner(System.in);
System.out.print("Enter an integer, the input ends if it is 0: ");
num = input.nextInt();
while(num!=0){
    count++;
    System.out.print("Enter an integer, the input ends if it is 0: ");
    num = input.nextInt();  
break;
}
System.out.print("total integers="+count);
}
int count++;    
}

Walking with Dinosaurs ... One of the worst movies I have ever seen!

And you watched it because?

Granted, your day was ruined because of all the other people's issues.

I wish i was a stick man!

I tried applying that, I still got an error? This is what i did:

import java.text.DecimalFormat;
import java.util.*;
public class Mean {
    public static void main(String [] args){
    Scanner s = new Scanner(System.in);
        double[]x = new double[10];
        int i;
        for(i = 0;i < 10; i++){
            x[i] = s.nextDouble();
        }
        double mean = mean(x, i);
        double deviation = var(x);
        System.out.println("The mean is " + mean); 
        DecimalFormat df = new DecimalFormat("#.##");
        System.out.println("The standard deviation is " + df.format(deviation));
}

public static double sum(double[] a) {
        double sum = 0.0;
        for (int i = 0; i < a.length; i++) {
            sum += a[i];
        }
        return sum;
    }
    public static double mean(double[]x, double i){
        if (x.length == 0) return Double.NaN;
        double sum = sum(x);
        return sum / x.length;
    }
    public static double var(double[] x) {
        if (x.length == 0) return Double.NaN;
        double avg = mean(x, 10);
        double sum = 0.0;
        for (int i = 0; i < x.length; i++) {
            sum += (x[i] - avg) * (x[i] - avg);
        }
        DecimalFormat myFormatter = new DecimalFormat("#,##0.00");
        return sum / myFormatter.format(Math.sqrt(x.length - 1));

    }
}

Hmmmm... that doesn't seem to work because it just repeats the string.

Granted, you figured it out... and then forgot it.

I wish i was the joker.

I still think it should have been done in two parts instead of three.

Same here...

Is this correct? I wrote a decimal format and it doesn't work. how do i correct this:

    return sum / myFormatter.format(Math.sqrt(x.length - 1));

I will submit the full code if needed.

Okay, so you mean like this:

import java.util.Scanner;
public class IntegerCount
{
public static void main(String[] args)
{
 while(true){

    Scanner input = new Scanner(System.in);
        System.out.print("Enter an integer, the input ends if it is 0: ");
int num = input.nextInt();

        if ( num == 0 ){
  System.out.println("No numbers were entered except 0");
}
else{
  System.out.println("The number of integers is " + count++);
}
}
}
}

I think i did it wrong? also, where do i put a break in this?

I was looking more at the 'costa coffee' on your staff t-shirt. Moonlighting are we Dani?

lol.

granted, you go to work instead.

I wish i lived in dubai

Yes, it is!!

I am guessing your setting up a mirror or a type of storage unit?

Okay, problem solved :D

I just basically refreshed chrome entirely :D

Check your computer preferences, it should say somewhere to stop automatic updates...

Also, what is your OS that your using? Windows, mac, etc.?

note, don't post questions like that in the community introduction

Welcome!

So here is what i have so far, am i using while(true) correctly? It says that is incorrect:

import java.util.Scanner;
public class IntegerCount
{
public static void main(String[] args)
{
 while(true){

    Scanner input = new Scanner(System.in);
        System.out.print("Enter an integer, the input ends if it is 0: ");
int num = input.nextInt();

        if ( num == 0 ){
  System.out.println("No numbers were entered except 0");
}
else{
  System.out.println("The number of integers is " + num);
}
}
}
}

So doing it like this works but for some odd reason I can not do a decimal format very well...? This should be the last correction for this questions, thank you guys!

import java.text.DecimalFormat;
import java.util.*;
public class Mean {
    public static void main(String [] args){
        Scanner s = new Scanner(System.in);
            double[]x = new double[10];
            int i;
            for(i = 0;i < 10; i++){
                x[i] = s.nextDouble();
            }
            double mean = mean(x, i);
            double deviation = var(x);
            System.out.println("The mean is " + mean); 
            System.out.println("The standard deviation is " + deviation);
    }
public static double sum(double[] a) {
        double sum = 0.0;
        for (int i = 0; i < a.length; i++) {
            sum += a[i];
        }
        return sum;
    } 
    public static double mean(double[]x, double i){ 
        if (x.length == 0) return Double.NaN;
        double sum = sum(x);
        return sum / x.length;
    } 
    public static double var(double[] x) {
        if (x.length == 0) return Double.NaN;
        double avg = mean(x, 10);
        double sum = 0.0;
        for (int i = 0; i < x.length; i++) {
            sum += (x[i] - avg) * (x[i] - avg);
        }
        DecimalFormat myFormatter = new DecimalFormat("#,##0.00");
        return sum / myFormatter.format((Math.sqrt(x.length - 1)));
    }
}

banning people who're critical of him from the white house press room takes care of that.

or people just don't bother with writing articles like that...

It says, "mark question solved" and i clicked it a few times... just to make it say the same exact thing

granted, there was nothing left...

I wish i was gandalf...

Elysium

@james, they are not exactly the same... the question began to change a bit on this thread, and so did the code.

Sorry, i won't "double post a thread" next time.

yo momma is so short she can surf on a popsicle stick

no deal, already got one (and 2 dogs)

a cockroach?

If nothing else, this thread has been worth it for the sheer joy of watching Alan get close to having a coronary at the keyboard as he attacks a completely virtual character with a brilliant display of Welsh wit. Yep, Welsh wit - who knew? ;)

This maybe a dumb question but who is alan?

According to a post on stackoverflow:

The dot (.) operator is used to access a member of a struct, while the arrow operator (->) in C is used to access a member of a struct which is referenced by the pointer in question.

The pointer itself does not have any members which could be accessed with the dot operator (it's acually only a number describing a location in virtual memory so it doesn't have any members). So, there would be no ambiguity if we just defined the dot operator to automatically dereference the pointer if it is used on a pointer (an information which is known to the compiler at compile time afaik).

@hicham, i am sure he has 99 problems and this ain't one of them anymore... ;)

It kind of reminds of that one stackoverflow feature they have (i would know because i was banned from their site a few times due to promoting daniweb :D).

Nice touch!

Welcome!

Welcome!

The author of this site has created a pretty nice one: http://the-echoplex.net/log/how-to-style-a-html-file-upload-control-using-css-and-javascript

it maybe pretty helpful but i think jorge's source maybe easier to follow.

I asked a question recently in the MySQL forum and when i look at my thread in the watched articles page, it says it has been marked solved even though i didn't mark it solved nor does the buttons on the thread indicate that it has been marked solved.

Is that a glitch or am I just seeing things?

on all of these it says that (in the error):
Table 'jstudent0.BOOK' doesn't exist

Here is the error log:

Your output has right initial contents, but is missing 1 characters at end
You have only a First Line Error

sdiff side by side difference your output versus solution....
Enter an integer: The pentagonal numbers are: 1 5 12 22 35    \ Enter an integer: The pentagonal numbers are: 1 5 12 22 35

Ummmm... i am kind of confused between the two.

@dev90, why do you have a (1) next to the while loop? May you do that on my snippet, it doesn't make sense at some parts (my tired and crazy logical side is kicking in)

i don't think i did it right...:

import java.util.Scanner;
public class Pentagonal {
public static void main(String[] args) {
int n,x,n1;
Scanner input = new Scanner(System.in);
System.out.print("Enter an integer: ");
n = input.nextInt();
n1=1;
System.out.print("The pentagonal numbers are: ");
while (n1<=n)
{
            x = (3*n1*n1 - n1)/2;
    if(n1==n)
System.out.print(x);
else
System.out.print(x+" ");
        n1++;
}   
}
}

there are quite a few flaws but finding the mean is pretty close (i need to figure out rounding on java) but standard deviation is way off.

This is what i got:

import java.util.*;
public class Mean {
    public static void main(String [] args){
        Scanner s = new Scanner(System.in);
            double[]x = new double[10];
            int i;
            for(i = 0;i < 10; i++){
                x[i] = s.nextDouble();
            }
            double mean = mean(x, i);
            double deviation = var(x);
            System.out.println("The mean is " + mean); 
            System.out.println("The standard deviation is " + deviation);
    }
public static double sum(double[] a) {
        double sum = 0.0;
        for (int i = 0; i < a.length; i++) {
            sum += a[i];
        }
        return sum;
    } 
    public static double mean(double[]x, double i){ 
        if (x.length == 0) return Double.NaN;
        double sum = sum(x);
        return sum / x.length;
    } 
    public static double var(double[] x) {
        if (x.length == 0) return Double.NaN;
        double avg = mean(x, 10);
        double sum = 0.0;
        for (int i = 0; i < x.length; i++) {
            sum += (x[i] - avg) * (x[i] - avg);
        }
        return sum / (x.length - 1);
    }
}

Oh, that makes a whole lot of sense!
Last question and I will be marking this solved.

How do you make it so that there isn't an extra space at the end?

Apparently it displays like this: 1[]2[]3[]4[]5[]6[]
Rather than: 1[]2[]3[]4[]5[]6

(Those brackets are spaces)

Thanks!

Read the second line of my just above post. you have to get input into n variable and that's your limit of the pentagonal number sequences.

That is the part i don't understand on making? May you show me how to do it, i have an idea on how to do it but i don't think i understand it very well.

Am I getting close to what you mean?

import java.util.Scanner;
public class IntegerCount
{
public static void main(String[] args)
{
    Scanner input = new Scanner(System.in);
        System.out.print("Enter an integer, the input ends if it is 0: ");
int num = input.nextInt();
int input = input++;
        if ( num == 0 ){
  System.out.println("No numbers were entered except 0");
}
else{
  System.out.println("The number of integers is " + input);
}
}
}

I have a feeling i did something horrificly wrong in that snippet of code...

Wow, thanks! I have been beating my head against the wall on this problem.

You know how to find standard deviation.Then just write an algorithm or make a flowchart and implement it in a for loop, as you have done to find the mean.
It seems that you have'nt tried.

not exactly, i have tried but apparently i can't take it from paper to code that easily.
I am going to see what i can come up with in the background.

Unfortunately, no. The best deep dish apple pies I ever had were made by a friend of mine but he moved away several years back.

You should have him send you some or give you the recipe.