0

I have a homework assignment that l started, but l ran into problems. Could you please look at my code and help me. The topic is as follow:

In this exercise, you will study the effect of several parameters used with RR scheduling. To solve the exercise, you will need to implement a discrete simulation to experiment with the performance of this strategy under different time slice lengths and different dispatcher overhead times. Do this by writing a simulation program to imitate the behavior of a single-CPU system that has a preemptive RR scheduler, and then collecting performance data regarding the operation of the simulation.

The Code is:

```
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
import java.lang.Math;
public class Simulation
{
public static void main(String [] args) throws IOException
{
BufferedReader console = new BufferedReader(new
InputStreamReader(System.in));
System.out.print("\n The time quantum (for Round
Robin algorithm)\n");
System.out.print("Time Quantum: ");
String input = console.readLine();
int quantum = Integer.parseInt(input);
int [] timequantum = new int[quantum];
for (int i=0;i<quantum;i++)
{
try
{
timequantum[i] = Integer.parseInt(in.readLine());
}
catch(NumberFormatException e)
{
System.out.println("You must enter a number!");
return;
}
}
//System.out.print("\n Dispatcher overhead times:\n");
//System.out.print("Dispatcher time");
//String input
//System.out.print("\n Arrival Time:");
//String input = console.readLine();
//int num = Integer.parseInt(input);
//int [] arrival = new int[num];
//for (int i=0;i<num;i++)
//{
// arrival[i]=console.readInt();
//}
///////////////////////////////////////////////////////////////////////////////////////////////
//System.out.print("\n Round Robin\n");
//float avgWait = getWaitRR(arrival, bursts, bursts2, quantum, num);
//System.out.println("\nAverage process waiting time:"+ avgWait);
//System.out.println();
}
static float getWaitRR(int [] p,int [] b, int [] b2,int q, int n)
{
float totalTurnAround = 0; //will hold the total TurnAround time
int[] turnAround=new int [n];
int avg=0,
totalBursts = 0;
for(int k=0;k<(b[n-1]);k++)
{
for(int i=0;i<n;i++)
{
if(b2[i]<q) //if the burst time for a process is less than the quantum
{
if(b2[i]!=0) //and if it is not equal to zero
{
for(int j=b2[i];j>0;j--)
{
avg++; //counts up all burst times
turnAround[i] = avg; //stores it in the correct array index
}
b2[i]=0; //makes sure there are no minus values
}
}
Else
{
for(int j=q;j>0;j--)
{
avg++; //counts up all burst times
if(b2[i]!=0) //if process bursts are != 0 then they haven't finished
turnAround[i] = avg; //over-right old time
}
b2[i]=b2[i]-q; //takes time quantum away from burst times, if it goes
below 0 it gets reset to 0
}
}
}
for(int i=0;i<n;i++)
totalTurnAround += turnAround[i]; //this gets the total turnaround time
totalTurnAround -= avg; //avg is the total burst time
return(totalTurnAround/n); //returns the average wait time
}
}
```

*Edited 3 Years Ago by mike_2000_17*: Fixed formatting