Displaying PHP result within HTML?

[justinmyoung]

I've searched through the forum, but I couldn't find an answer. How do you display a result within HTML?

Such as:

$query = "SELECT * FROM customers WHERE job_number='$jobnumber'";
	$result = mysql_query($query);
	while ($row = mysql_fetch_array($result)){
		echo $row['first_name'];
		echo $row['last_name'];

Thanks in advance.

[ryan_vietnow]

Could you please explain more what you want to display?

[justinmyoung]

I want to display the , , fields. Here's the script I have used to call up a result from my database, and the result is the echo $row['first_name'] , etc. I'm just trying to figure out how to wrap the result within HTML.

if(isset($_POST['submit'])) {
	$jobnumber=$_POST['jobnumber'];

	//connect

	$query = "SELECT * FROM customers WHERE job_number='$jobnumber'";
	$result = mysql_query($query);
	while ($row = mysql_fetch_array($result)){
		echo $row['first_name'];
		echo $row['last_name'];
		echo $row['email'];
		//etc...
	}
}
?>

Did I help clear it a little? Thanks for your help...

[ryan_vietnow]

there's no problem in your code that will display the results alright.Do you mean that you want to display the results in a specific area of an HTML page?

[justinmyoung]

I just want to display the results within a table or a list.

[ryan_vietnow]

just put the echo thing inside the table.

$query = "SELECT * FROM customers WHERE job_number='$jobnumber'";
	$result = mysql_query($query);
	echo "<table>";
        while ($row = mysql_fetch_array($result)){
		echo "<tr>"
                echo "<td>$row['first_name']</td>";
		echo "<td>$row['last_name']</td>";
		echo "<td>$row['email']</td>";
                echo "</tr>";		
//etc...
	}
        echo "</table>";

[justinmyoung]

I seem to be getting this error: Parse error: syntax error, unexpected T_ECHO, expecting ',' or ';' in getjobnumber.php on line 30

Here's how I wrote it:

<?php
if(isset($_POST['submit'])) {
	$jobnumber=$_POST['jobnumber'];

	//connect

	$query = "SELECT * FROM customers WHERE job_number='$jobnumber'";
	$result = mysql_query($query);
	echo "<table>";
	while ($row = mysql_fetch_array($result))  {
		echo "<tr>"
		echo "<td>$row['first_name']</td>";
		echo "<td>$row['last_name'];</td>";
		echo "<td>$row['email'];</td>";
		echo "</tr>";
		//etc...
	}
		echo "</table>";
	}
?>

Line 30 = echo "<td>$row['first_name']</td>"; It's highlighted in thick red. Thanks again.

[ryan_vietnow]

you have mistakenly put ";" in this line: echo "<td>$row['last_name'];</td>"; erase it and it will be fine.

[ryan_vietnow]

and also in here: echo "<td>$row['email'];</td>"; I am referring to the ";" in the middle.

[nav33n]

No..that isn't the problem.. The problem is missing ; in here..

echo "<tr>"

[ryan_vietnow]

OOPS!

[nav33n]

Beer mug ? Party time ? eh ? ;)

[justinmyoung]

$query = "SELECT * FROM customers WHERE job_number='$jobnumber'";
	$result = mysql_query($query);
	echo "<table>";
	while ($row = mysql_fetch_array($result))  {
		echo "<tr>";
		echo "<td>$row['first_name']</td>";
		echo "<td>$row['last_name']</td>";
		echo "<td>$row['email']</td>";
		echo "</tr>";
		//etc...
	}
		echo "</table>";
	}
?>

This still gives me a parse error: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in getjobnumber.php on line 30

[nav33n]

I dont see line 30 in that code snippet !
And btw, instead of echo "<td>$row['last_name']</td>"; Try, echo "<td>".$row['last_name']."</td>";

[effu]

$query = "SELECT * FROM customers WHERE job_number='$jobnumber'";
	$result = mysql_query($query);
	echo "<table>";
	while ($row = mysql_fetch_array($result))  {
		echo "<tr>";
		echo "<td>$row['first_name']</td>";
		echo "<td>$row['last_name']</td>";
		echo "<td>$row['email']</td>";
		echo "</tr>";
		//etc...
	}
		echo "</table>";
	}
?>

This still gives me a parse error: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in getjobnumber.php on line 30

You have two options:
--- Option 1 ---
Remove the single quotes ' from the $row
echo "<td>$row[first_name]</td>";
--- Option 2 ---
Change your echo to this (NOTE: the variable is surrounded by ". ." within the echo)
echo "<td>".$row."</td>";