Hi All,

I am making a web directory in which i have one field of url of website which is i am taking form a form. Now i want to do this when i will show this url on my site then this will fetch screenshot of that url on my site.

How i can do this using PHP code. Please help me to do so. I will be very appreciate of that person.


Recommended Answers

All 2 Replies

without having the exact code at hand id say you will need to use javascript in your href using the onmouseover function.

here is some good information on it http://www.w3schools.com/jsref/jsref_onmouseover.asp

to display the page should just be a case of having that javascript containing the URL of that paticular page

Be a part of the DaniWeb community

We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, learning, and sharing knowledge.