0
<?php
$host = "localhost";
$usr = "root";
$pwd = "";
$db= "DB";
conOpen($host,$usr,$pwd,$db);
function conOpen($host,$usr,$pwd,$db){
$con=mysql_connect($host,$usr,$pwd) or die ("Connection Failed ");
mysql_select_db($db,$con);}
$rows_per_page=5;
// database connection stuff here
$result=mysql_query("Select * from newsimage");
$pages=ceil(mysql_num_rows($result)/$rows_per_page);
if (!isset($screen))
  $screen = 0; else echo $_GET[screen];
/*
$start = $screen * $rows_per_page;
$sql = "SELECT nId FROM newsimage ";
$sql .= "LIMIT $start, $rows_per_page";
$result = mysql_query($sql);
$rows = mysql_num_rows($result);
for ($i = 0; $i < $rows; $i++) {
  $description = mysql_fetch_array($result);
  echo "\$description = $description[nId]<br>\n";
}
echo "<p><hr></p>\n";
// let's create the dynamic links now
if ($screen > 0) {
  $url = "z.php?screen=" . $screen - 1;
  echo "<a href=\"$url\">Previous</a>\n";
}
// page numbering links now
for ($i = 0; $i < $pages; $i++) {
  $url = "z.php?screen=" . $i;
  echo " | <a href=\"$url\"  onClick=\"window.location.reload(true)\">$i</a> | ";
}
if ($screen < $pages) {
  $url = "z.php?screen=" . $screen + 1;
  echo "<a href=\"$url\">Next</a>\n";
}*/
?>

I am using the above code for record navigation
But On Click on hyperlinks 1,2
I didn't get the next records

Please help me

5
Contributors
19
Replies
81
Views
3 Years
Discussion Span
Last Post by Borzoi
0

i used echo to check only that wheather $_GET[screen] has value or not
But it doesn't have

0

I agree with pritaeas

if (!isset($_GET[screen]))
  $screen = 0; 
else 
  $screen=$_GET[screen];

Edited by urtrivedi

0

$_GET[screen] should be $_GET["screen"] and will not have a value unless the URL of the page is appended with ?screen=value where "value" is the value.

0
<?php
$host = "localhost";
$usr = "root";
$pwd = "";
$db= "Dbase";
conOpen($host,$usr,$pwd,$db);
function conOpen($host,$usr,$pwd,$db){
$con=mysql_connect($host,$usr,$pwd) or die ("Connection Failed ");
mysql_select_db($db,$con);}
$rows_per_page=5;


$result=mysql_query("Select * from newsimage");
$pages=ceil(mysql_num_rows($result)/$rows_per_page);
if (!isset($screen))
  $screen = 0; else $screen=$_GET["screen"];

$start = $screen * $rows_per_page;
$sql = "SELECT nId FROM newsimage ";
$sql .= "LIMIT $start, $rows_per_page";
$result = mysql_query($sql);
$rows = mysql_num_rows($result);
for ($i = 0; $i < $rows; $i++) {
  $description = mysql_fetch_array($result);
  echo "\$description = $description[nId]<br>\n";
}
echo "<p><hr></p>\n";
// let's create the dynamic links now
if ($screen > 0) {
  $url = "z.php?screen=" . $screen - 1;
  echo "<a href=\"$url\">Previous</a>\n";
}
// page numbering links now
for ($i = 0; $i < $pages; $i++) {
  $url = "z.php?screen=" . $i;
  echo " | <a href=\"$url\"  onClick=\"window.location.reload(true)\">$i</a> | ";
}
if ($screen < $pages) {
  $url = "z.php?screen=" . $screen + 1;
  echo "<a href=\"$url\">Next</a>\n";
}
?>

The above code gives the result

$description = 1
$description = 2
$description = 3
$description = 4
$description = 5

| 0 | | 1 | | 2 | Next

But record navigation doesn't takes place

0

| 0 | | 1 | | 2 | Next

Show the generated HTML for this.

Try what happens if you remove the Javascript (onClick).

Edited by pritaeas

0

but i didn't used the script Javascript onclick
$_GET["screen"];
doesn't get any value..
I think page has to be submitted to get value in $_GET
but here is not any form submission..
Thats y $_GET doesn't get the value...

Any solution...?

0

but here is not any form submission

That's why I suggested to remove the onClick...

...and you still haven't shown me the output HTML.

Edited by pritaeas

0

Assuming the code is still as above, try:

$pageResult = mysql_query($sql);
$rows = mysql_num_rows($pageResult);
for ($i = 0; $i < $rows; $i++) {
    $description = mysql_fetch_array($pageResult);
    echo "\$description = $description[nId]<br>\n";
}

Edited by pritaeas

1

Your problem is with your IF statement on lines 14/15. You're checking the variable $screen before you're putting anything in to it:

if (!isset($screen))
    $screen = 0; else echo $_GET["screen"];

You neede to check it $_GET["screen"] is the one which is set:

if (!isset($_GET["screen"]))
    $screen = 0; else echo $_GET["screen"];
0

Oh..Thanks a lot Mr. Borzoi..
But i have one more issue left in it
and that is NEXT and PREVIOUS Link..
I want 4nos of link at once..
and on clicking NEXT button, next 4 links i.e (5,6,7,8) should be shown
Can u please help me in this issue..also..
I am very very thankful to you

0

The way you're passing information into the $url variable wouldn't work. Using the Previous link, your if statement is this:

if ($screen > 0) {
$url = "z.php?screen=" . $screen - 1;
echo "<a href=\"$url\">Previous</a>\n";
}

You'll want to pass the value of $screen - 1 into a different variable which you then pass into $url like this:

if ($screen > 0) {
$previous = $screen - 1;
$url = "z.php?screen=" . $previous;
echo "<a href=\"$url\">Previous</a>\n";
}

You might want a more generic variable name so you can use it with the Next link, which would be the same concept.

Incrementing or decrementing $screen with $screen++/$++screen and $screen--/$--screen wouldn't work as it would cause problems with the Next link.

0

If that has solved your problem, make sure you mark the thread as solved so that others who may have a similar problem can find the solution easier.

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