However , if your chat application(using sockets) works over intranet(LAN) successfully then it WILL and should work over internet also.. Check the source code whether the server and client IP's and port numbers are correct..
My purpose got satisfied.. When i first saw that question , i thought that it was a silly question but when i think deeply it's a kind of interesting , logical question. Eventhough i know the answer , just posted because to know different ideas and comments from you all people...
@Muralidharan.E... i like your straight forward answer....
@Majestics That's what my main intention in posting this question.. I already know the answer that int has a range.. but how many times does it is looping and what exactly is the value of c ..
Ok.. Read the user input (elements that are to be sorted ) into an array.. Then read the choice of the menu..
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int choice=Integer.parseInt(br.readLine());
Now using switch - case , write your actual sorting technique code in the appropriate cases.
switch(choice)
{
case 1:
{
//write your bubble sort logic here
break;
}
case 2:
{
//write your selection sort logic here
break;
}
case 3:
{
//write your insertion sort logic here
break;
}
}
Java SE 7 is officially released today! After nearly five years of collaboration within the worldwide Java community, Java Platform, Standard Edition is ready for download! It's an important step in Java’s evolution. The major features of Java SE 7 are:
• Project Coin- many small language changes that add up to a big boost in productivity for developers • The Fork/Join Framework - facilitates parallelism for mulit-core processors • The New File System API (NIO.2) - provides the ability to perform many basic file system operations natively • InvokeDynamic - makes it easier to run other languages on the JVM
Hi.. Well.. i am doing a project in J2ME . I heard that j2me midlets cannot run on some of the (latest) mobile phones and there involves a hectic work to deploy them in mobile. Is that so? . How to deploy my j2me midlet in mobile phone. ? Copying the jar file (or jad file) into the mobile is only thing that i should do inorder to deploy my app? My project is basically a banking application. what are the minimum mobile requirements that i should have inorder to make my project work successfully?
If a person is not happy , then it doesn't mean that he don't know happyness . It is because life had tought him some lessons which made him like that.
I encountered a strange problem today when i tried to run my java program from a batch file. I have a fullscreen mode java application and i tried to run the application from a batch file .Now the problem is images are not being loaded when i run my program using batch file. I executed manually from the command prompt and was shocked to see that even now the problem is not fixed. I generally use my favourate Editplus editor. When i execute from my editor, there is no such problem and everything works fine.
I rec-checked the path of images twice and there's no problem with that.
I really dont know what's stopping the images from being loaded when i execute from batch file.
One of the great advantages of java is built-in memory allocation and management.
if java fail to clean the resources on close... kind of poor background for java.
There is no question of java failing to clean the resources. Once the application is closed and JVM starts quitting ,JVM is responsible to clean the memory and all the space allocated for JVM will automatically be deleted from RAM. JVM is responsible for calling the garbage collector and looking all that.. While in C we should take care of memory management which increases programmers overhead.
Closing the window is just like any other operation performed on it like opening,resizing,minimizng,maximizing etc..
Just assume that closing the window is like somewhat similar to hiding the window. So here in this case ,we are performing an simple close operation on window but the reference to that object still exists unless we explicitily make it null.
It still contains the same reference as that of before closing the window. Closing the window or disposing the window doens't mean destroying the JFrame object. We can make visible the window even after destroying it.
As destroying a window or closing it is just a operation performed on the window.
The jframe contains the same reference as before even we destory the window...
Passing the exam will be easy but scoring more is what which shows the understanding of java.
Anyway...writing the exam may cost but preparation will cost nothing.
Preparation is what i was emphasizing from starting post and whether taking the exam or not is the secondary thing and depends on one's own interest. Perhaps we should take certification exam only if we feel we are strong technically(and ofcourse financially).
Technology costs. But knowledge doesn't ----Anonymous
off course, SCJP does no longer exist. the name has been changed when Oracle took Java over from Sun
Yeah..scjp still exists but its now OCJP..however the pattern and syllabus of the exam is the same except the name.
Its well known fact that the preparation for certification exams cannot be done in a week or two. If you think that you are a java nerd and you have very good basics then certification is an valuable option.
If you are more interested in java ,starting preparation for Oracle certification from an highschool onwards is a good option.
If you want to check nearest prime numbers , then why checking it from i=1 onwards. Checking from reverse manner i.e (i=num-1) whould be a better approach.
Anyway...here's the solution..
import java.io.*;
class Twin
{
public static void main(String[] args) throws Exception
{
int twin[]=new int[2],count=0,k=0;
System.out.println("Enter the range :");
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int range=Integer.parseInt(br.readLine().trim());
for(int i=range-1;i>=1;i--)
{
for(int j=2;j<i;j++)
{
if(i%j==0){count++;break;}
}
if(count==0)twin[k++]=i;
count=0;
if(k==2)break;
}
System.out.println("The twin primes are "+ twin[0] +" and " +twin[1]);
System.out.println("sum is "+(twin[0]+twin[1]));
}
}
one appear twice because when the loop first executes with value 0 , case 0 is executed and also case 1 gets executed because there is no break after the case 0.
so now the output becomes
zero one
Now , the i value is 1 . hence case 1 will be executed which prints one more "one"
finally the i value is 2 which makes case default case gets executed
Hence the output is
zero one one Unknown number
I hope now you understand the reason why one printed twice..
There's no code in paint() method because there is no requirement.
I am not worried about exceptions here in this case since it has no complex code to throw such Heavy Exceptions .. However .. The only point is that code in keyTyped() method is not updating the components to window .
