Hi I have a little question which I have partly tried but I am not completely sure if I am doing it correctly.
Heres the question
Does the equation 2x=26(mod32) have any solutions? If it does determine them and if not then explain why.
Down below is how I approached it: -
2x=26(mod32)
2x-26=32k
x-13=16k
therefore x=16k+13
This is where I get stuck, I don't know which values to use for K to give the final solutions for x.
Can anyone help me.
Mus.
Jump to PostHi I have a little question which I have partly tried but I am not completely sure if I am doing it correctly.
Heres the question
Does the equation 2x=26(mod32) have any solutions? If it does determine them and if not then explain why.
Down below is how I approached …
Hi I have a little question which I have partly tried but I am not completely sure if I am doing it correctly.
Heres the question
Does the equation 2x=26(mod32) have any solutions? If it does determine them and if not then explain why.
Down below is how I approached it: -
2x=26(mod32)
2x-26=32k
x-13=16k
therefore x=16k+13
This is where I get stuck, I don't know which values to use for K to give the final solutions for x.
Can anyone help me.
Mus.
You've completely solved the problem. Congratulations!. Any integer value of k gives a solution. for instance, k= 0 gives the solution x = 13. This is a solution because the statement 2*13 = 26 mod 32 is true. k = 1 gives the solution x = 29, etc. You could write the general solution as you have, x=13+16k, or you could write the general solution as x = 13 mod 16.
Hi Mus,
I think the first answer is 29 because 2x29-26=32
Moshi
The "first" answer? Any number congruent to 13 or 29 (mod 32) is correct. There is no "first" answer.
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