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Does anyone know how to convert a jk flip flop to a d flipflop in computer architecture or circuits?

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Dani AI

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A one-line conversion: drive J with D and K with the complement of D. From the JK next-state equation Q+ = J Q' + K' Q, substitute J = D and K = !D to get Q+ = D (Q' + Q) = D. That makes the JK act as a D flip-flop; implementation typically needs only a single inverter (or complementary outputs from preceding logic) to feed J and K.

Practical notes and caveats: this equivalence assumes an edge-triggered JK device and correct timing. D must meet setup and hold around the clock edge or metastability can occur. For level-sensitive master–slave JK implementations, avoid changing D while the latch is transparent. Watch propagation delay and skew between the inverter and the JK inputs; place the inverter near the flip-flop if possible. Asynchronous Set/Reset pins remain effective and must be handled per the device datasheet. Using a dedicated D-FF IC is often the simplest practical route (as observed), and consulting a logic-design text is useful for timing subtleties (as suggested). For device behavior and timing references see D flip-flop and JK flip-flop.

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Member Avatar for Nick Evan

Use a 74377 instead of a 74xx ?

Member Avatar for jwenting

or just read a book on de design of logic circuits, like you should have been told to get on your required reading list.

Member Avatar for mrnutty

Here, less work for me to explain.

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