Help :textbox first 3 letters

[PutingPanday]

HELP I NEED TO GENERATE A RANDOM ID FOR MY EXAM...

NEED TO GET THE FIRST 3 LETTERS OF THE FIRST NAME....How do I do this?been searching for hours..

help greatly appreciated

[M.Waqas Aslam]

hello !
you can use substring() to perform this task , try this

txtTest.text = txtFirstName.text.Substring(0, 3).ToString

if you found this ans useful please mark this thread solved and vote me :P

Regards

[pritesh2010]

for generating random number use random class for that. see below Example which gives you some idea how to generate Random Number.

Private Function GenerateRandomString(length As Integer) As String
	Dim charPool As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890"
	Dim rs As New StringBuilder()
	Dim rnd As New Random()
	While System.Math.Max(System.Threading.Interlocked.Decrement(length),length + 1) > 0
		rs.Append(charPool(CInt(rnd.NextDouble() * charPool.Length)))
	End While

	Return rs.ToString()
End Function

//call this function like this

txtTest.text = txtFirstName.text.Substring(0, 3).ToString &_ GenerateRandomString(3)

[Mitja Bonca]

HELP I NEED TO GENERATE A RANDOM ID FOR MY EXAM...

NEED TO GET THE FIRST 3 LETTERS OF THE FIRST NAME....How do I do this?been searching for hours..

Just as simple as waqasaslammmeo explained!! Use Substring() method.
1st number inside brackets is starting index (in your case is 0, becuase you want to start from beginning)
2n number is th lenght if the string (3 in your case).

This is it.

[thines01]

Be sure to check the length of the string to make sure it's at least 3 characters (or whatever size of the substring).