When button is pressed from Forms of MS-Access, a file open dialogue box is displayed. I need the VB code.
newwin
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Jump to Postwhich vb code u need
Jump to PosthI,
Use "Microsoft Common Dialog Control " , add it from Projects>Components:
"Microsoft Common Dialog Control 6.0"add it to form and in command Click :
CommonDialog1.ShowOpen FileName = CommonDialog1.FileName
Set "Filter" property to filter particular File extensions
Regards
Veena
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