Hi, I have installed Oracle 11g (latest version 11.2.0.1.0) on my system. During the installation it didnt ask me to set username or any password. I'm unable to start sql plus because i dont have the username and password. Can anyone tell me what is the default username and password or what is the default password for SYS or SYSTEM? Thanks, VC

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My ps's motherboard is burned and i was just trying to see where or how i would get a motherboard for my TEK 6633 all in one pc. I am from Namibia and noone here is unable to help me.

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When I try to execute my jar file through the command prompt by typing: java -jar myJar.jar It returns an error message saying that it can not access the jar file. Why is this? myJar.jar is the exact name of my jar file.

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Hello all, I am trying to take input from user using scanner. The problem is, when the loop starts, it skips taking input for the first iteration. Here is the code: import java.util.Scanner; public class TrigTriangles{ public static void main(String[] args){ int N; double a,b,c; double A,B,C; Scanner s = new Scanner(System.in); C=90; char[] charArray; String input; System.out.println("Enter N: "); N = s.nextInt(); for(int i = 0; i < N; i++){ System.out.println("Enter line: "); input = s.nextLine(); System.out.println(input); /* charArray = input.toCharArray(); if(Character.isUpperCase(input.charAt(0))){ System.out.println("It is uppercase!"); } */ } } }

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Hi. I seem to be unable to login. I rcieved an email saying I had got an endorsment so tried to login but it doesn't recognise my password. I have tried to reset my password 3 times now. I get an email with a link to click, but when I do I am redirected to an 'oops' page sying you don't know who I am. Just to make this post I have had to register a new account (with a different email address). Any idea how I can get login? Zagga

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I have a clone computer with the following specification, Intel i5, 4GB RAM, 250GB hadr disk, ATI Radeon graphic card, PCI-E network adapter running on Window 7 Pro 32bit. The problem is the computer unable to shutdown. When I shutdown it will go off and after a second or so it will turn on back again by itself and boot back to Window. I have try changing the power supply, reformat the Window, change hard disk and change RAM but no solution. The last resort of course is to change the motherboard which I try not to. That's why I …

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HI, I am writing unit test cases for silver light view model. When i am trying to mock edmx context, i am getting errors as in the screen shot. Please suggest how to solve the issue. ![9559cdb1d93cc91198a358bac62eeca5](/attachments/large/2/9559cdb1d93cc91198a358bac62eeca5.png "9559cdb1d93cc91198a358bac62eeca5") Thanks kvk

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try { /* Class.forName ("sun.jdbc.odbc.JdbcOdbcDriver"); String loc = "jdbc:odbc:Library"; String filename = "C:\\Users\\Krishal Lad\\Desktop\\Library.mdb"; String database = "jdbc:odbc:Driver={Microsoft Access Driver (*.mdb, *.accdb)};DBQ="; database+= filename.trim() + ";DriverID=22;}"; // add on to the end con = DriverManager.getConnection (database);*/ Class.forName("sun.jdbc.odbc.JdbcOdbcDriver"); String database = "jdbc:odbc:Driver={Microsoft Access Driver (*.mdb,*.accdb)};DBQ=Library.mdb;"; System.out.println("connecting to database..."); Connection conn = DriverManager.getConnection(database); } catch (ClassNotFoundException cnf) { JOptionPane.showMessageDialog (null, "Driver not Loaded..."); System.exit (0); } catch (SQLException sqlex) { JOptionPane.showMessageDialog (null, "Unable to Connect to Database..."); sqlex.printStackTrace(); System.exit (0); } This is not able to connect to the Library database. I have created a ODBC data source Library. This is the …

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Cek this syntax: root@ubuntu:/opt/lampp# ./lampp startmysql XAMPP: Starting MySQL...ok. root@ubuntu:/opt/lampp# ./lampp status Version: XAMPP for Linux 1.8.3-3 Apache is running. MySQL is not running. ProFTPD is running. I already start mysql yet it's still unable to run. Why is it?

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Hi Everyone, Thanks for viewing this post. I have placed the code below in the MASTERPAGE.master.cs Label user = (Label)Master.FindControl("lblHidden123"); The control named lblHidden123 is in one of the Child page that refer to MASTERPAGE.master.. This control lblHidden123 is a normal label field, visible true. When i try to access it in the MASTERPAGE.master.cs with the code above, it is always returning me NULL. Is there anything wrong with the code? Please kindly advice me and do let me know if my post is unclear. Thanks!

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I decided to use the stored procedures in MySQL. I am able to retrieve only one row value in OUT paramater, but when the returned result contains more than one row, I get nothing! Please see the simple code below for stored procedure which I add it to phpmyadmin direct: DELIMITER ;; DROP PROCEDURE IF EXISTS SelectContacts ;; CREATE PROCEDURE SelectContacts(OUT mobileNumber VARCHAR(255)) BEGIN SELECT accounts.mobile_number FROM accounts WHERE accounts.account_id = 1 OR accounts.account_id=2 INTO mobileNumber; END ;; ///////// Now to call the procedure from PHP: ///////////////////////////////////////// $result = mysql_query("CALL SelectContacts(@mobileNumber)"); while($row = mysql_fetch_assoc($result)) print_r($row); /// no output because the …

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<?php include ('pages/dbconnect.php'); $rekdep=mysql_query("SELECT * FROM t_org ORDER BY dept, com ASC"); echo "<table class='gridtable'>"; echo "<tr><tr><th> Departement</th><th> Commune </th><th> ORG </th><th>Animal</th>"; echo "</tr>"; echo "</tr>"; $odl_dept = null; $odl_com = null; $odl_org = null; while($dep=mysql_fetch_assoc($rekdep)){ //List of department if($dep['dept']!=$odl_dept){ echo "<td>".$dep['dept']."</td>"; } //display blank td if the same department is found a second time else{echo "<td></td>";} //List of commune if($dep['com']!=$odl_com){ echo "<td>".$dep['com']."</td>"; } //display blank td if the same commune is found a second time else{echo "<td></td>";} // list of organizations if($dep['nom']!=$odl_org){ echo "<td>".$dep['nom']."</td>"; $org= $dep['nom']; //display the number of animal for each organization $qcab= mysql_query("SELECT sum(`qte_an`) FROM `t_animal` …

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I want the word "gallery" to do a css3 3D rotate transition and reveal the words "art/art2" unfortunately I'm having a mud of a time getting it to work. **HTML** <div class="wrap"> <div class="gallery">Gallery</div> <div class="back"><a href="" class="link_a">Art</a><a href="" class="link_b">Art2</a> </div> **CSS** .gallery {font-size:4em;color:orange;} .gallery a:hover {color:orange;position:absolute;-webkit-transition: all .1s ease-in-out;-webkit-perspective:600px; none;-webkit-transform-style: preserve-3d;} .back {font-size:4em;position:absolute;top:2px;} .back a:hover {color:grey;-webkit-transform: rotateX(180deg);-webkit-perspective: 500px;}

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Hi Dw I've created some few ASP using Visual Basic .Net and the files when I publish it (exporting from IDE to a folder) are in .aspx format and the problem is that I didn't find the hosting that support this kind of format they support .asp so my question is that where can I get a hosting that support this if anyone know one preferable South Africa because I'm running out of time so we need a host that we will deposit and reflect immediately. Also another question is that is there any way to reload the master page …

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**here is my coding. i want user unable to select data in select box once it is selected in the first select box(hide/remove).i add the javascript. but its not working. any solution?** **peralatan.php** <?php require_once('Connections/iventori.php'); ?> <?php $id = $_GET['idpinjaman']; $colname_Recordset1 = "-1"; if (isset($_GET['idpinjaman'])) { $colname_Recordset1 = (get_magic_quotes_gpc()) ? $_GET['idpinjaman'] : addslashes($_GET['idpinjaman']); } mysql_select_db($database_pinjaman, $pinjaman); $query_set1 =sprintf("SELECT * FROM pemohon a,pinjaman b WHERE a.id_pemohon=b.id_pemohon AND b.id_pinjaman='%s'", $colname_Recordset1); $set1 = mysql_query($query_set1, $pinjaman) or die(mysql_error()); $row_set1 = mysql_fetch_assoc($set1); $totalRows_set1 = mysql_num_rows($set1); mysql_select_db($database_pinjaman, $pinjaman); $query_set2 =sprintf("SELECT * FROM inventori"); $set2 = mysql_query($query_set2, $pinjaman) or die(mysql_error()); $row_set2 = mysql_fetch_assoc($set2); $totalRows_set2 = mysql_num_rows($set2); function …

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hello i am having issues with my website. i have been notified by several people using ipads, that they are unable to click any links, add themselves to the mailng list etc... http://naniboujou.com everything looks fine (design, layout etc..) but links are unclickable! form fields un fillable... what gives? thanks pj

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The End.