how we load 12.0.0.0 in a python dictionary
jwalajoseph
0
Newbie Poster
Recommended Answers
Jump to PostDo you mean as an IP address? Need a little more specifics than that...
dicts require an identifier (usuall a string), and the object(s) that the identifier refers to... so...
ip_addys = dict() ip_addys['first_ip'] = 12.0.0.0should probably work... There are other ways to directly insert …
Jump to PostYou must also convert the ip number to normal number or keep it as string. I have posted as one of my first Code Snppets functions for the conversion.
All 5 Replies
ryantroop
177
Practically a Master Poster
Do you mean as an IP address? Need a little more specifics than that...
dicts require an identifier (usuall a string), and the object(s) that the identifier refers to... so...
ip_addys = dict()
ip_addys['first_ip'] = 12.0.0.0
should probably work... There are other ways to directly insert into a dict as a key=>value pair, but the simplest way is to use the above (in my opinion).
TrustyTony
888
pyMod
Team Colleague
Featured Poster
You must also convert the ip number to normal number or keep it as string. I have posted as one of my first Code Snppets functions for the conversion.
jwalajoseph
0
Newbie Poster
i tried the following code.
ip_addys = dict()ip_addys['first_ip'] = 12.0.0.0
but it shows a syntax error occured in 12.0.0.0
Gribouillis
1,391
Programming Explorer
Team Colleague
12.0.0.0 is not a valid python literal. Use "12.0.0.0" which creates a str instance.
ryantroop
177
Practically a Master Poster
yeah, sorry... it would need to be a string.
Be a part of the DaniWeb community
We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.