campkev

int intTemp = Convert.ToInt32(Console.Readline())

this is a community help forum. We help you with your problem, we don't do everything for you. Tell us what you have tried and what problems your are having and we will help you solve them. We won't do everything for you.

to find the number of digits in int x [code] if (x < 0) x = -x; int count = 1; x = x/10; while( x > 0) { count++; x = x/10; } [/code]

screenshot?

create table tblname ( fieldname datetime default getdate() )

What error messages/symptoms are you getting? Post code from where you think problem might be happening. If you want help with your homework, you are going to have to give us some details

where is this ("lb.Click += new System.EventHandler(engCat_Clicked);") piece of code located? without seeing all of the code, i would hazard a guess that it is inside an if(Postback){ } section

SQL express is free, or at least it was a month or two ago when I downloaded it. I can't imagine that would have changed. Also sqlexpress supports sub-queries, which I don't believe access does. Also, in my experience, sqlexpress recovers better from errors than access. I have had instances …

System.Web.Mail.MailMessage mail = new System.Web.Mail.MailMessage(); mail.To = "whoyouwantmailtogoto@yoursite.com"; mail.From = "whoyouwantmailtoshowfrom@yoursite.com"; mail.Subject = "Subject"; mail.Body= "Message from " + txtboxName.Text +"<BR>"+"Email Address: " + txtboxEmailAddress.Text +"<BR>"+"Message: " + txtboxMessage.Text; mail.BodyFormat = (System.Web.Mail.MailFormat.Html); //mail.Send(); System.Web.Mail.SmtpMail.SmtpServer = "yourmailserver"; System.Web.Mail.SmtpMail.Send(mail);

use javascript to focus on the third one

select the info that you want into a datatable, set the datatable as the datasource for the dropdown. call the databind function. and make sure you specify in the dropdown control which columns have correspond with the DataValueField and DataTextField

[code] string testString = Session("ssNtUser").ToString(); int i = testString.IndexOf("\\")+1; if(i > 0) { testString=testString.Substring(i); } [/code]

huh?

problem is nothing is returend if the try block throws an exception and it is caught by the catch block. Simplest way to fix this is to return a "blank" sqlcommand. Change [code] catch (Exception ex) { Console.Write ("Error in connection : "+ex.Message); } [/code] to [code] catch (Exception ex) …

How about something like this [code] private void DateSubmit_Click(object sender, System.EventArgs e) { DateTime date1, date2; bool date1OK, date2OK; date1 = new DateTime(1,1,1); date2 = new DateTime(1,1,1); try { date1 = Convert.ToDateTime(Date1.Text); date1OK=true; } catch { date1OK = false; } try { date2 = Convert.ToDateTime(Date2.Text); date2OK=true; } catch { date2OK …

um, have you never been in school?

here, save this in a file called pc.js [code] var calWindow; var targetField; var today = new Date(); var dayofmonth = today.getDate(); var startDate; var selectDate; var prevMonth; var prevYear; var currMonth; var currYear; var nextMonth; var nextYear; var days = new Array('Sun','Mon','Tue','Wed','Thr','Fri','Sat'); var months = new makeArray(12); function makeArray(arrayLength) …

Having a problem connecting via dsn on windows 2003 x64. Keep getting : ADODB.Connection error '800a0ea9' Provider is not specified and there is no designated default provider. Code works fine on regular server 2003

kinda hard to tell, but what happens with your first example if there is an exception during someAction()

It makes sense just fine, she is just using the wrong word. She means dll. what you are looking for is in the bin subdirectory. All you need is to put the all non-codebehind pages(*.aspx, global.asax, etc) in the folder on the new server. You don't need the code behind …

do you need your app to send and email, or are you trying to do a whole email interface to check email, send email, etc?

short answer is No. There is no direct way to disable the back button so that it is greyed-out and user cannot click on it. However, there are some tricks using javascript which might be able to give you the results you need,although they won't be as pretty. One I …

are you trying to put it on the aspx page or in the codebehind?

<SCRIPT LANGUAGE="JavaScript"> if (this.name!='fullscreen'){ window.open(location.href,'fullscreen','fullscreen,scrollbars') window.close(this) } </script>

[CODE] update tablename set memssn = cast(substring(memid,1,9) as int) where substring(memid,1,9) like replicate('[0-9]',9)[/CODE]

try adding group by customer to the end of the query

Ok occasionally I get the following error message on my site System.String Substring(Int32, Int32) Error: Length cannot be less than zero. Parameter name: length here's the wierd part, I don't use that Substring function, I use System.String Substring(Int32) whose only parameter is start. So I am getting an error from …

I know how to use System.Web.Mail to send emails. Anybody know how to send encrypted emails?

>Doesn't it increment by itself? it depends on how that column is setup in the database. Is it set up as an identity column?

what you probably want to use is a gridview (or datagrid, if your are not on 2.0) and bind it to the database

this is the c# forum. try the c++ forum

i would do this: [code] private string accountNumber; private int accountNumberLength; public string AccountNumber { get { return accountNumber; } set { StringBuilder sb = new StringBuilder(value); while(sb.Length < accountNumberLength) sb.Add(" "); accountNumber = sb.ToString(); } } [/code]

you are confused, int is not limited to less than 10,000 in sql server. the limit is around 2 billion. (2^31)-1 to be precise

I am betting that you are just doubleclicking the file to open it. Yes? If you put it on your site and browse to it as a normal user would, you probably aren't going to get that problem.

I would instantiate an application variable in the application on start pulling the value from whereever it is saved Increment it in session onstart Save it back to whereever in application onend

[QUOTE=AbuBakar]I want to show images in one column of datagrid against each Product Id by using Picturebox which is coming from Database[/QUOTE] you need to access the onitemdatabound event [quote] want to raise events against the click and mouseover events of each picturebox[/quote] so add them [quote] Moreover I also …

what kind of database are you using, SQL, access?

actually you don't want to be able to decrypt it. what you do is encrypt the password and save that in the database when the user logs in, encrypt the password the input on the login screen and compare that to the encrypted password in the database here is a …

Go to [url]http://www.connectionstrings.com[/url] It is your friend. Bookmark it.

give us table setup and what data you have in those tables

This isn't a problem as I have already solved the problem, just trying to figure out why it happened. Ok I have a field that is type money. I wrote a stored procedure that updates this field, however, I made the datatype for the parameter to get passed in a …

or simply "select 50. / 100"

you could also use buyerName.Contains(TextBox3.Text) buyerName.BeginsWith(TextBox3.Text) buyerName.EndsWith(TextBox3.Text)

[code=sql] select * from persons where (prefix like '%'+@input+'%' or firstname like '%'+@input+'%' or lastname like '%'+@input+'%') and address like '%'+@addressinput+'%' [/code]

I think you want something like this Select distinct pt.ProductID from Products pt left join Rating RT on pt.productid = rt.productid order by IsNull(Min(rt.Rating),0)

get rid of the square brackets around the varchar(255) and it will work fine. For that matter, why are you putting them around the datatypes anyway? I've never seen anyone do that.

post your code that is giving this error

i cannot even ping that address. You probably need to talk to your network administrator. This looks like a networking problem, not a ASP.Net problem

ok, i am assuming that you want a name for all id's. if a has an entry use that, otherwise use the name from b. also assuming that B has an entry for every id. if those assumptions are correct, then this should work [code] select b.id, isnull(a.name,b.name) as [Name] …

so, what is your question?